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I can find axial tilt of planets easily, but that doesn't specify the direction of that tilt, i.e. planet's rotation axis may be anywhere in circle defined on a sphere by axial tilt value. And I can't google for obliquity direction as it only gives me obliquity value, not it's direction. Even NASA's HORIZONS only gives obliquity value. I expect there should be another angle, either from main body equinox, Earth's equinox, ascending node or maybe periapsis, that with axial tilt and orbital elements would define direction of planet's rotation axis. I know that rotation axis is often if not usually precesses, but that takes thousands of years, and compared to time from J2000 it's practically neglectable (or at least it's easier to find precession rate and make a correction for it, knowing some starting value).

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  • $\begingroup$ I'm no physicist, but wouldn't the axis of rotation for the planet vary relative to the star the planet is orbiting over the coarse of the planet's orbit? The only alternative meaning I think you might mean is the axis of rotation relative to the rest of space outside the solar system in question, is this the case? $\endgroup$ Commented Aug 24, 2021 at 13:02
  • $\begingroup$ Obliquity (axial tilt) is set as angle from perpendicular of orbital plane and axis of rotation. It does depends on main body (star, in case of planets) only as it's in one of orbit's foci, but not defined by it in any way. That's why I've said that there's whole circle of possible values for any given obliquity - imagine plane (which is orbital plane), perpendicular vector from it and any unit vector tilted from that perpendicular at some specific angle, that gives a whole range of vectors, all of which would be correct, but only one would represent an actual axial tilt of a planet IRL. $\endgroup$
    – Aberro
    Commented Aug 24, 2021 at 13:15
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    $\begingroup$ The orientation of a planet's rotation axis (its polar axis) changes very slowly. Earth's axis is tilted at an angle of ~23.5°, and its orientation takes ~26,000 years to go through a cycle. Currently, it points near Polaris (the pole star). Please see en.wikipedia.org/wiki/Axial_tilt $\endgroup$
    – PM 2Ring
    Commented Aug 24, 2021 at 13:29
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    $\begingroup$ I just discovered a table of north poles of the Sun & all the planets: en.wikipedia.org/wiki/Axial_tilt#Solar_System_bodies $\endgroup$
    – PM 2Ring
    Commented Aug 24, 2021 at 13:32
  • $\begingroup$ There are some relevant references linked in the comments of this question: astronomy.stackexchange.com/q/58099/16685 $\endgroup$
    – PM 2Ring
    Commented Jul 26 at 8:29

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Essentially, the idea is to calculate de right ascension and declination values of the north pole of each planet using special formulas. Each formula is planet-specific, due to its unique interactions with other bodies in the solar system. The values of the right ascension and declination are expressed using the planet's ecliptic equator (the intersection of the body's equatorial plane and the International Celestial Reference Frame (ICRF), which is fixed to the stars and centered on the solar system barycenter).

Reference System (Credit IAU Working Group)

Once, the north pole is determined, the equatorial plane can be deducted (the plane orthogonal to the vector defined between the north pole and the planet center and containing the planet center) as well as the line of nodes that define the intersections of the ICRF plane and the planet's equatorial plane.

The last step is to properly orient the north pole to a given direction. This is achieved by calculating the angle W that specifies the position of the line of nodes. Again, the formula to calculate the value for W is planet specific. Using the value of W, the north Pole axis can be rotated around the ICRF z-axis (0,0,1), to position the line of nodes properly.

In each formula, the right ascension, the declination, and the position of the prime meridian are calculated using:

T = interval in Julian centuries (of 36525 days) from the standard epoch J2000
d = interval in days from the standard epoch J2000
The standard epoch is JD 2451545.0, i.e. 2000 January 1 12 hours TDB

To learn more about this works for each planet, take a look at the following document:

IAU Working Group on Cartographic Coordinates and Rotational Elements: 2009

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  • $\begingroup$ The term "line of nodes" normally refers to the intersection between the body's orbital plane and the reference plane. But here you're using it to refer to the intersection between the body's equatorial plane and the reference plane. See en.wikipedia.org/wiki/Orbital_node You should clarify that, otherwise it may confuse some readers. $\endgroup$
    – PM 2Ring
    Commented Jul 26 at 7:37
  • $\begingroup$ BTW, you must give proper attribution for any material that you post that you did not create. That includes images and quoted text. Please see physics.stackexchange.com/help/referencing That page focuses on text but it also applies to images. $\endgroup$
    – PM 2Ring
    Commented Jul 26 at 7:42

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