Let's say there is a capacitor as shown in the figure, $K_1$, $K_2$, $K_3$, $K_4$ being the dielectric constant of each quadrant. (the dimensions of all four parts are equal.)
Let $C_1$, $C_2$, $C_3$, $C_4$ be the capacitance of the respective dielectrics, $A$ be the area of cross section of all four dielectrics and $d$ be the width of all the four capacitors. I am supposed to find the equivalent capacitance of this combination.
I was able to come up with two ways to solve this question:
Take $K_1$, $K_2$ in series and $K_3$, $K_4$ in series, add the two equivalent dielectrics in parallel.
Take $K_1$, $K_3$ in parallel and $K_2$, $K_4$ in parallel, add the two equivalent dielectrics in series.
Should I solve it by method 1 or 2, or are both correct, or is there some other method that I am not aware of?