1
$\begingroup$

Given a function $f(x)$ and its Fourier transform $\tilde{f}(k) = \int_{-\infty}^{\infty}f(x) e^{ikx}dx$, if I decompose the Fourier transform as $$\tilde{F}(k) = A(k)e^{ikl(k)}$$ Under what conditions on $f(x)$ can I say that $l(k)$ is a slowly varying phase factor ($\dfrac{d l}{dk}$ is small), i.e. when does the Fourier transform look approximately sinusoidal $\tilde{f}(k) \sim \sin(kd + \phi)$?

For example, the functions $\dfrac{\sin kd}{kd}$, which is the Fourier transform of a box centered at the origin and $\cos(kd) e^{-k^2}$, the Fourier transform of a symmetric shifted gaussian both are acceptable. In both these cases, $f(x)$ has a finite support ($f(x) = 0$ for $|x| >$ some L). Does having a finite support help in general?

$\endgroup$
1
  • 2
    $\begingroup$ This question might be better answered on mathematics. $\endgroup$
    – Triatticus
    Commented Mar 23, 2021 at 23:42

0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.