$1$ mole of an Ideal gas performs a reversible cycle with 2 adiabatic and 2 polytropic processes.
$A(P_0,V_0,T_0)$ to $B$ with $V_B=V_A/\lambda$ with an adiabatic process.
$B$ to $C$ with a polytropic process where $P=C_1V^{1/2}$
$C$ to $D$ with an adiabatic process.
$D$ to $A$ with a polytropic process where $P=C_2V^{1/2}$
Find the cycles efficiency and draw the PV diagramm of the cycle.
Solution:
Since there is heat exchange only during the two polytropic processes we can easily calculate the efficiency to be $η=1-\frac{Q_{out}}{Q_{in}}=1-\frac{T_C-T_B}{T_A-T_D}$ since we know $C_{23}=C_{41}=C$ since the processes share the same $k=-\frac{1}{2}$.
$T_B=1.6T_A$ can easily be calculated using the fact that AB is adiabatic and PV=RT.
My problem is that I can find no way to calculate sates C and D. This is because i have only 3 equations to calculate $(PC,Vc,Pd,Vd)$. These equations are:
$P_C=C_1V_C^{1/2}$
$P_D=C_2V_D^{1/2}$
$P_C V_C^{γ}=P_D V_D^{\gamma}.$
So the two polytropic processes could end anywhere and $T_C$,$T_D$ cannot be determined. Same goes for the Pressure and Volume at those points. What I am saying is that in this $P-V$ diagramm the red line could be moved anywhere to the left or to the right and where exactly it is affects the efficiency of the cycle.
I tried using the fact that $\Delta U=0$ for the whole cycle but it didnt get me anywhere. Is there anything I'm missing?