Ratio of $F_{net}$ acting on a body to its weight?

Question

The acceleration of a body, expressed as a multiple of $g$, is $always$ equal to the ratio of the net force on the body to its weight.

What does this statement mean? Is it referring to the g-force acting on a body? But that equals net force acting on the body divided by its mass (force acting per unit mass). I don’t quite understand the highlighted statement.

That’s Page no. 120 from the book ‘University Physics with Modern Physics’, 13th edition.

Answer 1

Starting from Newton's 2nd law: \begin{align} F_\text{net} &= ma\\ \therefore\quad F_\text{net} &= ma\,\frac{g}{g}\\ \therefore\quad \frac{F_\text{net}}{mg} &= \frac{a}{g} \end{align} where $g\approx 9.8$ ms$^{-2}$ is the acceleration due to (Earth's) gravity.