# Resonant frequencies in air filled closed cylinder

I want to calculate the resonant frequencies of a closed cylinder covered with rigid walls. The cylinder is of dimensions: diameter = $$1m$$, length = $$1m$$. Would this fundamental mode formula be correct to use in this case:

$$f = \frac{v_{sound}}{2L}$$

I think it is only valid for one-dimensional ducts such that diameter $$\ll$$ length but I am not sure about this. Could you please help me out with an explanation and how the above formula was derived and in which conditions is it valid to be used?

• This formula is for a cylinder open at one end. Is this your type of cylinder? – nasu Mar 21 at 19:51
• Yes that's right. Thank you. I have just corrected the formula. – Becay Mar 22 at 4:52

This can be derived by simply using the a very fundamental equation that λ𝑓=𝑣.
For fundamental or the lowest frequency the system can achieve, the wavelength should be maximum, for a given wave speed.

Putting the maximum wavelength of the wave using the diagram, you would get the desired relation.
This relation is derived by using the basic definitions of wave and hence is valid in general for waves where the two end points to be considered are nodes.

• Meaning that the formula can also apply even in three dimensional spaces? – Becay Mar 28 at 9:38
• Yes, i believe so, also actually this disturbance happens in 3 dimensional space, where the air moves in packets of compression and rarefaction. – Sidharth Giri Mar 28 at 19:20