The reflected light you refer to will not give you interference fringes, because the path difference between the two routes (via top of lens and via another surface) is too big. If the path difference is greater than a few wavelengths (perhaps about 50* but see Farcher's comments below) – more if you are using laser light) the wavelength-spread of the light will mean that some wavelengths will interfere constructively and others destructively (and everything in between), so the reflected light that you refer to will just contribute to a brighter background, without giving its own fringes (that is rings).
On the other hand, light reflected from the top surface of the flat glass and from the bottom surface of the lens will produce fringes, because near the centre (the point of contact) the path difference is so small. For example, if the radius of curvature of the bottom surface of the lens is 1.0 m, then at 5 mm from the centre, $\Delta y = 125 \times 10^{-7} \text{m},\ $ which is probably about 20 wavelengths. Note that further out, even these fringes start to blur out, for the reason given in my first paragraph.