I don't understand how we get this value and what it means, does it mean that this charge distributed over earth surface so charge density is small? Or it distributed over the volume?
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$\begingroup$ The fair-weather field is about 100 V/m, maybe that integrated over Earth's surface gives this charge? Calculate it yourself. $\endgroup$– user137289Commented Jan 21, 2018 at 15:02
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