# Ion acoustic wave regime

I am fairly new to plasma physics and am making a project on the Ion Acoustic Wave. We have discussed Landau-damping in a plasma where we took the electrons to have a Maxwellian distribution and considered ions as immobile. The idea of the project is to generalise this to the case where we also take ions into account.

In my attempt to do so, I have used Python to solve the dispersion relation numerically. I find that for a temperature ratio $T_{el}/T_{ion}= 10^4$ and mass ratio $m_{el}/m_{ion}= 1/2$ the damping effect is weaker for the IAW than when the ions were considered immobile. How could I understand this result more intuitively? I was expecting the wave to damp faster as there are now two species absorbing energy from the wave. I also found that for heavier ions, the IAW gives almost identical results as the initial plasma model.

• The original idea behind IAWs was that $T_{e}/T_{i}$ needed to be greater than 3 otherwise the instability that radiates the waves would be suppressed. In the 1970s and 1980s, several authors (e.g., Christian Dum) did a lot of work on this topic and found that the instability dependence on $T_{e}/T_{i}$ could be reduced or even ignored in the presence of electron heat fluxes, temperature gradients, beams, etc. Note that the original concept is horribly flawed in that we never observe single, isotropic Maxwellians for either ions or electrons in space plasmas. – honeste_vivere Dec 14 '17 at 13:29
• Thanks! This explains why the influence seen in my figures is almost negligible! – Plasmaths Dec 14 '17 at 18:53

• The wave $\omega/k$ is in the tail of the dispersion relation of the ions (since $v_{thi}\lt\lt \omega/k$ for ions in ion-acoustic waves).
• The wave is near the maximum of the electron distribution (since $v_{the}\gt\gt \omega/k$ for electrons in ion-acoustic waves).
This means that the gradient of both dispersion relations is small at $v=\omega/k$ which means that the number of electrons (ions) with velocities moving slightly faster then the wave is approximately equal to the number of electrons (ions) moving slightly slower. The wave does work on these slower electrons and has work done on it by the faster electrons. Since they are approximately equal in number the net transfer of energy from the wave to the resonant particles is small and there is consequently little damping.
• I have added a figure - $k$ in units Debye length – Plasmaths Dec 14 '17 at 18:51