What is the mathematical proof for this?


marked as duplicate by Bill N, John Rennie, SRS, Kyle Kanos, AccidentalFourierTransform Feb 2 '17 at 12:59

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  • $\begingroup$ It is not always true: For instance, if the waves have different amplitude or different frequency they will not form a standing wave $\endgroup$ – user126422 Feb 2 '17 at 1:53
  • $\begingroup$ @AlbertAspect How can you show this? $\endgroup$ – Goldname Feb 2 '17 at 2:14
  • $\begingroup$ program it and view the result $\endgroup$ – user18764 Feb 2 '17 at 2:36
  • 2
    $\begingroup$ -1. No research effort. A citation for "I heard it was true always" would be useful! See Standing waves due to two counter-propagating travelling waves of different amplitude. $\endgroup$ – sammy gerbil Feb 2 '17 at 2:52
  • $\begingroup$ @sammygerbil Your link does not include mathematical derivation. I heard it was true from a TA which is totally irrelevant. "No research effort" Wrong, unless you can pull up my search history and prove otherwise $\endgroup$ – Goldname Feb 2 '17 at 3:27

Wave going into positive direction has the equation:

$$p(x)=\sin(x+\omega t)$$

Into the negative direction:

$$n(x)=\sin(x-\omega t)$$

Their sum:

\begin{align} p(x)+n(x)&=\sin(x+\omega t)+\sin(x-\omega t) \\ &=\sin(x)\cos(\omega t) + \cos(x)\sin(\omega t) + \sin(x)\cos(\omega t) - \cos(x)\sin(\omega t)\\ &=2 sin(x)cos(\omega t) \end{align}

As you can see, the wave on the bottom is a standing sine wave, whose amplitude is multiplied by the original frequency of the moving waves.


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