So, I was practising some radioactivity physics problems for a test and I got on an easy but quite tricky question :
Given the element $\rm Co^{60}_{27}$ with a half life of $t_{1/2} = 5.2 $ years and its radioactivity is equal to $A = 0.5~\mathrm{ uBq}$ Compute its mass $m$ .
After using some formulas I got to this :
$$ m = \frac{M\cdot t_{1/2}\cdot A}{\ln2} $$
The way I got to this is as follows :
$$ A = N_0 \cdot \lambda$$ $$ A = \frac{m \cdot N_a}{M} \cdot \frac{\ln2}{t_{1/2}}$$
Where :
- $M$ is the molar mass of $Co^{60}$
- $\lambda$ is the radioactivity decay constant
- $N_a$ is the avogadro num
My question is that whether I should convert the $t_1/2$ to seconds or just use years ? Also should I convert $A$ to $\rm Bq$ instead of $\rm uBq$ ? Or is it possible to work directly without converting the units ?