I have read the book "Introduction to special relativity " by Robert Resnick In the book I have found that "If the distance between the clocks is L, one observer will see the other clock lag his by 2L/c when other observer claims that they are synchronous" in the section 2.1(The Relativity of Simultaneity) How does this result come?? I did not understand..!!
$\begingroup$
$\endgroup$
1
-
$\begingroup$ Section 2.1 of Resnick does not contain what you say it contains. Please be specific with your question. $\endgroup$– ProcyonCommented Apr 16, 2016 at 11:22
Add a comment
|
1 Answer
$\begingroup$
$\endgroup$
This is not really a relativistic effect. This is simply a consequence of information delay due to the speed of light being finite. $L/c$ is the time it takes for light to travel the distance $L$. Hence the information transmitted by light over the distance $L$ will be delayed by $L/c$. If the two clocks were exactly synchronized (in the stationary reference frame), both observers would see the other clock lagging by $L/c$. If one observer sees the two clocks as synchronous, that means her/his clock is actually lagging by $L/c$, which means the other observer would see it as lagging by $2L/c$.
