# Thermodynamics of supercooled water

Now that it's been freezing outside for the last few days, I experimented a bit with supercooling. I've left a bottle of clean water outside for a few hours, and behold, when I shook the bottle, the liquid began to freeze rapidly, as expected.

However, not all of the water froze, only about half of it. This got me thinking.

I reasoned that happens because freezing releases heat, and that heat raises the temperature of the ice and remaning water to 0$^\circ$C, at which point the freezing stops.

To try to quantify this, set

• $H_f = 334000 \frac{J}{kg}$, the "freezing heat" (enthalpy of fusion) of ice,
• $c_i = 2110 \frac{J}{kg\cdot K}$, specific heat of ice,
• $c_w = 4181 \frac{J}{kg\cdot K}$, specific heat of water,
• $M$, initial mass of supercooled water,
• $T_0$, initial temperature of supercooled water,
• $m$, mass of ice at a given moment,
• $T$, temperature at a given moment.

We suppose that the energy released by the freezing of a $\textrm dm$ mass of ice is used up by raising the temperature of both the already frozen ice ($m$) and the remaining water ($M-m$):

$$\textrm dm \cdot H_f = c_i m \cdot\textrm dT + (M-m)c_w \cdot\textrm dT$$

By rearranging we get a linear differential equation for $m(T)$:

$$\frac{\textrm dm}{\textrm dT}+\frac{c_w-c_i}{H_f}m = \frac{c_w}{H_f}M$$

The solution of this equation, using the initial condition that at $T=T_0$, $m=0$:

$$m = M \frac{c_w}{c_w-c_i}\left[ 1-e^{-\frac{c_w-c_i}{H_f}(T-T_0)} \right]$$

This looks neat, however, plugging in the actual values of the constants, $T = 0^\circ$C and $T_0 = -6^\circ$C, I get that little more than 7% of the water should freeze - as opposed to more than half, as I've observed. What's worse, the formula can be used to calculate the starting temperature required to freeze all the supercooled water: $$T_{all} = \frac{H_f \log\frac{c_w}{c_i}}{c_i-c_w}=-110.26^\circ \textrm C$$ which seems absurd.

Where is the error in the calculation above?

I've made a number of assumptions which may or may not hold:

• the constants are really constant. I think this is a good approximation for $c_w$, a not that good but still acceptable approximation for $c_i$, and I suppose it holds to $H_f$ to some extent as well.
• there is no heat transfer with the environment, i.e. the bottle is a closed system. The process seemed fast enough (a few seconds at most) for this to be a good approximation.
• the system is in a thermal equilibrium at all times and the heat released by the freezing of the ice is distributed evenly in the emerging ice-water mixture. Now this is where I have doubts. Precisely because of the process happening so fast, this might not be true at all. However, acknowledging the presence of temperature variations makes the problem order of magnitudes harder: one has to solve a system of partial differential equations that take heat transfer, the shape of the bottle and \$deity knows what else into account. • To be completely honest, I would doubt that what you described actually happened. Yes, boiling and freezing can occur due to disturbances when starting from a non-equilibrium state, but this is a very very small fraction of the mass. I doubt your math is wrong. Your numbers show the exact thing that I would have qualitatively predicted. Latent energy of boiling or freezing compares to a temperature change on the order of magnitude of$100^{\circ} C$. That was my expectation all along. Such large amounts of supercooling are not physical. We can't account for that observation. – Alan Rominger Feb 5 '12 at 23:34 ## 4 Answers I'm answering my own question. Apparently this is one of those rare cases when the physicist must doubt what he observed -- or what he thought he observed -- and believe the numbers his theory yielded instead. From further experiments I've noticed that the ice tends to form thin plates inside the supercooled water once the crystallization process starts -- this form of ice is apparently called dendritic ice. When the starting temperature of the water was about$-10^\circ$C, the resulting ice-water mixture still contained a lot of water by the time the process finished, and most of it was trapped between those thin ice plates. The latter fact would make it hard to measure the mass percentage of water exactly. I've found some scholarly articles studying this process -- mostly in the context of formation of ice plugs in pipes. In  they measured the temperature at a number of points inside a capsule full of supercooled water during ice formation. From the time-dependent temperature profiles in the article it is obvious that my model above (that energy released by the freezing ice heats up all of the water and ice) is completely wrong. The process happens so fast (at a rate of a few cm/s, depending, among other factors, on the temperature), that the heat transfer between the already frozen (thus heated to$0^\circ$C) and still supercooled regions is practically negligible. However, based on the observation that ice and water appears well mixed in the already frozen region, we can put forth a new model: the released latent heat of fusion is used up locally and quickly in the boundary layer of the expanding frozen region. As a particular region at the boundary freezes, it heats up rapidly to$0^\circ$C (or close to it), and heats up the water surrounding it. Since the ice plates thus formed are relatively close to each other, the resulting region containing ice-water mixture will mostly be free of temperature inequalities, and those inequalities that do exist will be damped quickly. Therefore the thermal profile of a volume of supercooled liquid undergoing freeze-out will consist of two flat regions, with a relatively sharp boundary between. It would be quite interesting to look at the process with a thermal infrared camera. Such an observation could confirm or reject the model above. To my knowledge, no one published such an observation -- if such a publication exists, I'd be very interested in seeing it. A video made by such a camera would be especially enlightening. With some simplifying assumptions (spherical container full of supercooled liquid with uniform temperature, and a single nucleation source at the center), the simple model above could be made quantitative, but I haven't done that yet. 1 Juan Jose Milon Guzman, Sergio Leal Braga: Dendritic Ice Growth in Supercooled Water Inside Cylindrical Capsule, 2004 There is a simpler way to do the calculation, though using it also gives me 7% of the water freezing. The heat needed to warm the water from T degrees below zero is simply: $$E = MTC_w$$ where$M$is the mass of the water,$T$is the degrees below zero and$C_w$is the specific heat of water (assumed constant over this range). The heat released when a mass$m$of the water freezes is: $$E = mL_{f}$$ where$m$is the mass that freezes and$L_{f}\$ is the latent heat of fusion. Assuming the system ends up at zero degrees you can just set the two equal, and you get:

$$\frac{m}{M} = T \frac{C_w}{L_f}$$

But, just as you found, plugging the numbers in gives 7% of the water frozen.

I suspect that the 50% ice you saw was actually 7% ice with a lot of unfrozen water trapped within the matrix of ice crystals. If you're feeling in an experimental mood you can put a known mass of warm water into a thermos flask and measure it's temperature, then drop in your bottle and measure the temperature change. Actually, I wish I'd though of doing that - I wonder if my nephews would be interested in try the experiment ...

• You could also try to measure the volume change as the ice melts again and infer the real percentage of ice crystals from that - easy enough if you can get it to become supercooled in a straight-sided bottle with some air at the top. – Nathaniel Feb 6 '12 at 15:32

In your opening statement you said “…….heat raises the temperature of the ice and remaining water to 0oC at which point the freezing stopped.”

I don’t believe the freezing stopped unless you placed the bottle in a warm environment.

Supercool water begin the freezing process only after latent heat is released and the temperature of the water is raised to 0oC by that heat (1). The amount of ice produced at moment that latent heat is first released in roughly proportional to the depth of supercooling and the thermal mass of the container that the water is in. Once latent heat is released freezing will continue until all the water in the container is frozen; if the container remain in a sub-zero environment.

(1) When does hot water freeze faster then cold water? A search for the Mpemba effect, James D. Brownridge, A, J. Phys. 79, 78 (2011)

• "I don’t believe the freezing stopped unless you placed the bottle in a warm environment." - I brought the bottle inside before disturbing it. However, I have trouble believing your statement: "Supercool water begin the freezing process only after latent heat is released and the temperature of the water is raised to 0oC by that heat". Isn't latent heat the energy difference between the frozen (crystallized) and liquid states? That would imply that it's released concurrently with, and because of the crystallization process. – kikuchiyo Feb 7 '12 at 20:31

Like you say, there seems to be something odd happening here. I have seen videos of water from a domestic fridge freezer being poured from a bottle and instantly forming a mound of ice. It is very hard to believe this mound, even though looking rather slushy, only contains a few percent of ice.

Is it possible that the supercooled water contains some of the ordered structure that occurs in ice and which is responsible for the latent heat of freezing. This would be seen as an apparent increase in the specific heat of water as it cools below 0 deg C as the water takes on some of the structure of ice, and a reduction in the latent heat when freezing eventually occurs, because the water already has some of the ordered structure of ice.