The lifetime for the $2p \rightarrow 1s$ transition in hydrogen is $1.6 \times 10^{-9}$ s. The natural line width for the radiation emitted during the transition is approximately...
Their solution:
The natural line width, $\Gamma$, is \begin{align}\Gamma &= \frac{\hbar}{\tau} \\&= \frac{\hbar}{1.6 \times 10^{-9}}{\rm Hz} \\&= h \cdot \frac{1}{2 \pi \cdot 1.6 \cdot 10^{-9}} {\rm Hz} \\&\approx h \cdot 10^8 {\rm Hz}\end{align}
Therefore, the answer (C), 100MHz, is correct.
I don't understand why the $h$ isn't multiplied. $100 {\rm\,MHz} = 10^8\,{\rm Hz}$, but leaving the $h$ there is like multiplying by $10^{-34}$, and none of the answers have an $h$ in them.
What am I missing?