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Consider the two diagrams below (ignore the velocities), enter image description here

Consider the situation in the right hand picture where we have a rod connected to the earth. Let us now say that the muon is created at the end of the rod, both frames (the earth and muon frame) most agree on this fact, since the laws of physics are the same in both frames. Then it should be obvious that according to the muon the rod is length contracted and thus it has a shorter distance to travail then an observer in the earth frame would say the muon had to travail. Now consider the left hand diagram where the rod is instead connected to the muon (and therefore at rest with respect to it). In this frame the rod will therefore be contracted to someone at rest in the earth frame compared to the muon frame (and thefore the observer in the earth would say the muon has a shorter distance to travil then someone in the muon frame would say). It should be clear that that these two arguments contradict one another. So why is the first analysis, where the length is contracted in the muon frame correct whilst the second is wrong.

(note that the rods are included simply for illustration)

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If the rod is connected to the muon, inertia suggests it has the same velocity as the muon and the rest frame of the rod is the same as the rest frame of the muon. So the muon-connected rod has its proper length in the muon's rest frame.

Likewise if the rod is connected to the earth, it has its proper length in the earth's rest frame.

The rod is always longest in the rod's rest frame, and has a contracted length in all other reference frames.

But what is the rod for? Suppose we want to use the rod to measure the muon's flight distance, so that the muon is born at one end of the rod and decays at the other. (For sake of argument we'll assume we can predict exactly when the muon will decay, rather than the half-life which is averaged over many different decays.) The rod in the earth's frame is pretty easy: the decay end is at our detector on the ground, and the birth end is somewhere in the upper atmosphere.

The rod attached to the muon is more subtle: the rod and the muon, in that reference frame, both have zero velocity, so the muon dies at the same end of the rod where it was born! In its rest frame the distance traveled by the muon is zero.

This is why we talk about length contraction in one case and time dilation in the other. The muon's rest frame is actually kind of boring: the muon sits alone, at rest, at the origin, and waits to die while the universe rushes around it. Keeping track of whether it's time to decay or not is essentially the only job that the muon has, which means that the decay always takes (on average) the "proper" time. Length contraction of the earth-atmosphere thickness is the only way to reconcile the muon's proper lifetime with the observational fact that we get lots of muons at sea level.

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  • $\begingroup$ Sorry, I think you may have misunderstood my question, but have expressed what I was trying to say in a better way. Now both frames would say that the rod (attached to them) is shorter in the other frame (due to Lorentz contraction), but when we do the classic muon decay question, finding how many muons make it to the earth we always say that the length is contracted in the muon frame and time dilated in the earth frame. My question was trying to ask why it is this way round and not the other? $\endgroup$ – Quantum spaghettification Jan 11 '15 at 14:47
  • $\begingroup$ @Joseph Better? $\endgroup$ – rob Jan 11 '15 at 15:11
  • $\begingroup$ Yes, but I still think we have a contradiction. If we attach the rod to the earth then in the muon frame the muon would say the earth moves a distance $d_1$, and an observer in the earth frame would say the muon moves a distance $d_2$, in this case $d_1<d_2$. But when we attached the rod to the muon we get $d_2<d_1$ contradicting the first inequality, please can you try and explain this. (sorry I know my question should have been better worded) $\endgroup$ – Quantum spaghettification Jan 11 '15 at 15:27
  • $\begingroup$ If we attach the rod to the muon, the distance the muon travels along the rod is zero. The reason for the difference is that the rod moves. $\endgroup$ – rob Jan 11 '15 at 15:29
  • $\begingroup$ yes but the earth is moving in the muon frame and it moves the length of the rod $\endgroup$ – Quantum spaghettification Jan 11 '15 at 15:30

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