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I'm doing an EPQ (mini college research paper) on gravity, and I found a site that explained things in simple terms. I am having trouble understanding how Einstein came to his revelation space-time was curved.

Einstein also realised that the gravitational field equations were bound to be non-linear and the equivalence principle appeared to only hold locally.

and Einstein said

If all accelerated systems are equivalent, then Euclidean geometry cannot hold in all of them.

Can anybody help?

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1 Answer 1

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Here's a simple demonstration:

Consider flat space (i.e. Minkowski), viewed in a rotating frame (in e.g. cylindrical coordinates one just replaces $\phi$ by $\phi'=\phi+\omega t$). One can calculate (without too much trouble) that, in these coordinates, a spatial line element can be expressed in terms of the canonical cylindrical coordinates as $$ d\ell^2=dr^2+dz^2+\frac{r^2d\phi^2}{1-\frac{\omega^2r^2}{c^2}}$$ Now, note that if we consider a unit disc in the $z=\text{constant}$ plane, we find $$d\ell=\frac{2\pi}{\sqrt{1-\frac{\omega^2}{c^2}}}>2\pi\hspace{1cm}\iff \omega>0$$

The startling conclusion is that this observer will measure the circumference of a disc of radius $r$ to be $C>2\pi r$ for any $\omega>0$. Hence, Euclidean geometry does not hold universally, even in flat space, if we relax the assumption that 'inertial frames' are somehow privileged, i.e. if we take this calculation seriously. Realizing that there is a need to consider (relatively) accelerating frames as equivalent was one of the major breakthroughs that needed to be made in order to arrive at the theory of general relativity.

Note that this example of the spinning disk was raised quite quickly after the advent of special relativity, and that it sparked quite a lively debate, influencing Einstein's thinking on relativity.

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  • $\begingroup$ But wouldn’t the whole metric, including $g_{t\mu}$ be still of flat space time, Minkowski space time? Wouldn’t the Reimann tensor vanish just like it does for the metric written in an accelerating coordinates ( hyperbolic motion) in flat space time ? The whole space time would still be flat, Minkowskian,right? Just changing coordinates can’t change the flat Minkowskian space time to a curved one? $\endgroup$
    – Shashaank
    Commented Mar 2, 2021 at 9:01
  • $\begingroup$ Do you mean that only the spatial submanifold will be curved rather than being flat, while the whole space time is still flat? $\endgroup$
    – Shashaank
    Commented Mar 4, 2021 at 7:35

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