For circular motion to occur a centripetal force is required. In the case of a turning bicycle, where does the centripetal force come from, since the force of friction is not great enough and the normal force acts perpendicular to the ground?
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4$\begingroup$ Force of friction is strong enough in most cases. For very high speeds, the roads are banked (the road is built obliquely so that a component of the normal reaction acts as the centripetal force). $\endgroup$– thunderboltCommented May 9, 2019 at 8:10
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1 Answer
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The frictional force is quite sufficient for providing the centripetal force to turn. It is only at high speeds that friction may not be enough and you may skid.
