Why system approach does not consider flow energy (flow work)?

Question

The total energy of a simple compressible system consists of 3 parts namely the kinetic energy, potential energy and the internal energy. The total energy of a control volume consists of an additional form of energy called the flow energy.

Why in system approach to fluid flow don't we consider the flow energy (Pv) even though the fluid element in the system has a pressure which can change (without the volume changing)?

Here I am trying to understand the energy equation with reference to the system approach and control volume approach to fluid flow (Lagrangian and Eulerian description).

Answer 1

Both Boundary work and Flow energy are analogous to each other.

As one can easily understand what boundary work is, I'll show how flow energy is analogous to Boundary work.

Consider a fluid flowing though a pipe of Area $A$, lets assume thin section of fluid $dX$ which has to flow through a distance $L$ through that pipe. Now for the liquid to move that distance of $L$, the liquid behind that thin section will be pushing it ($dX$) to move through that length $L$. So this is work done by fluid behind on the thin section ($dX$) to move a length $L$. Which can be written as : $ Force \times Distance = (Pressure \times Area) \times (L) = (P \times A ) \times l = PV $

Now in the above example the thin section($dX$) is analogous to Piston in a control mass system and fluid behind it is pushing just like the fluid in a cylinder piston device. Now suppose the liquid is not flowing through the pipe, then there is no work being done on the thin section $dX$ by the liquid behind to move, so work done is zero which is flow work, so stationary liquids don't have flow work.

Hope this helps. You can see Example 4.5 in Thermodynamics by Cengel and Boles.