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The pressure of a gas at the triple point of water is $1.35\ \text{atm}$

First, we have the temperature and pressure of the triple point of water:

$T=0.01\ \text{ºC}$

$P=0.006\ \text{atm}=611.73\ \text{Pa}$

From that two known values, how do I obtain the pressure of a gas -in this case $1.35\ \text{atm}$-?

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    $\begingroup$ You don't obtain the pressure of the gas from the values of the triple point of the water, the information about the triple point is there so you can obtain a temperature value. In which context does the quote appear? $\endgroup$
    – Wojciech Morawiec
    Commented Feb 7, 2017 at 20:10

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I feel like you are missing information here. Using the ideal gas equation $$ p/T = nR/V$$ one could calculate the preassure if more information was given.

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