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In thermodynamics, the triple point of a substance is the temperature and pressure at which the three phases (gas, liquid, and solid) of that substance coexist in thermodynamic equilibrium.

enter image description here

Is the existence of Triple point a coincidence?

how does one explain existence of a three way junction?

Is it the junction of a part of the graph that is under the solid,liquid and gaseous phase?

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  • $\begingroup$ physlink.com/Education/AskExperts/ae282.cfm Refer it. $\endgroup$ Feb 18, 2016 at 8:13
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    $\begingroup$ Look at it this way: just try to draw a phase diagram where gas, liquid, and solid do not have a vertex in common. $\endgroup$ Feb 18, 2016 at 15:17
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    $\begingroup$ What do you mean "why does it exist"? The lines have to meet somewhere (well, one could imagine a diagram that has those lines not meeting, but if you think about it, that substance would behave very strangely). $\endgroup$
    – ACuriousMind
    Feb 18, 2016 at 16:38

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The three way junction is there because that is where the three phases (solid, liquid and vapour) of a substance can coexist in thermodynamic equilibrium with one another. At all other temperatures only two (or one) phases can co-exist together in equilibrium.

You might say that you can have ice in a beaker of water with the top of the beaker covered and eventually the ice and the water and the water vapour will all reach the same temperature. So here you have all three phases of water in equilibrium with one another and so it must be the triple point. That is not so because there is also air present which upsets the equilibrium.

Referring to the graph which you have provided which happens to be for water I think?

I imagine that you had a sample of pure water in a container and you could vary the pressure and the temperature within the container.

The phase diagram shows you for each value of pressure and temperature what will be happening to the water inside your container.

For example suppose you kept the temperature of the container at a fixed temperature which was above the triple point temperature but below the critical temperature and varied the pressure within the container starting from a very low pressure, every time waiting for the water to reach an equilibrium state.

Initially inside the container there would be just water vapour but as the pressure increased you would reach a pressure (actually called the saturated vapour pressure) when both water liquid and water vapour could coexist with one another.
The blue line is the saturated vapour pressure against temperature graph.

Increasing the pressure further you would have only water liquid in your container.

If you repeated the experiment at the triple point temperature, at low pressures you would first have water vapour but at a certain pressure you would find that all three phases of water, solid, liquid and vapour, are coexist together in equilibrium.

Increasing the pressure further would result in only water liquid being in your container.

The temperature at which the solid, liquid and vapour phases are in equilibrium is well defined enough to make triple point cells containing pure substance reference points for the calibration of thermometers.

You can gauge the extent to which purity is defined by reading the section Unit Of Thermodynamic Temperature (kelvin) p113-114. They even define the isotopic composition of the water.

I not know what you meant by the word coincidence. The triple point is not unique to water.

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    $\begingroup$ I believe the OP asks why the point of common adjacency to all 3 phases exists. That's a simple topology question. $\endgroup$ Feb 18, 2016 at 15:18
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    $\begingroup$ @CarlWitthoft If you think I am not answering what was asked i will delete my answer. I have tried to show the reason for there being a unique point on the graph where all three phases exist. "What is the explanation of existence of a three way junction?" was one of the questions $\endgroup$
    – Farcher
    Feb 18, 2016 at 15:51
  • $\begingroup$ @Farcher By thermal equilibrium you mean thermodynamic equilibrium? Right? $\endgroup$
    – SRS
    Feb 2, 2019 at 22:28
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    $\begingroup$ @SRS Many thanks for pointing out my error (repeated many times) which I have now corrected. $\endgroup$
    – Farcher
    Feb 3, 2019 at 8:10
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The existence of a triple point is not a coincidence at all. It will be a necessary feature as soon as you have three different phases in your phase diagram that can all be reach from each other.

It's like when you have three countries that all share borders. By geometry alone there has to be a point were the borders intersect.

The position of the triple point, however, will of-course depend on the details of the substance at hand.

EDIT: Because thermodynamic phase diagrams can have critical points where phase boundaries terminate, the above rough explanation is not entirely true. One can think of situation where the third phase borders the critical region, as bellow:

The phases bu to triple popint

However, I know myself of no such phase.

Apart from this I don't see how you can avoid the triple point. (I'm happy to be shown another (non-trivial) example where the triple point is avoided).

IN COMMENT: You may also be interested in looking at Gibbs' phase rule.

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    $\begingroup$ i didn't downvote... but your geometric sense is wrong, for there can be 1. closed phase boundary curves 2. parallel phase boundary curves which can lead to no triple points... $\endgroup$
    – Bruce Lee
    Feb 18, 2016 at 8:34
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    $\begingroup$ I don't understand why is this downvoted without even leaving a comment? It is clearly not universally true, but it is at least partially correct. However, I would have added a link to the Gibbs phase rule. $\endgroup$ Feb 18, 2016 at 8:38
  • $\begingroup$ I accept you comments. One learns things every day. $\endgroup$ Feb 18, 2016 at 9:42
  • $\begingroup$ @BruceLee Interesting - so do you know of any material which acts that way? The only possibilities I see are (1) requires nonzero pressure at 0Kelvin to solidify, (2) requires nonzero pressure at 0 Kelvin to liquify. I'm not sure this is possible under various laws of physics. $\endgroup$ Feb 18, 2016 at 16:44
  • $\begingroup$ @CarlWitthoft: Helium is the only thing without a gas-liquid-solid triple point, simply because it doesn't really have a solid phase. $\endgroup$
    – ACuriousMind
    Feb 18, 2016 at 17:53
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Because liquids don't exist∗. A liquid is just a wannabe gas.

There are two phases of matter - solid (cold) which turns into gas (hot) at a certain temperature (273 K for H₂O). This process is called sublimation.

However, if heated above the sublimation temperature in a region with a certain level of pressure, the pressure prevents full sublimation. Some particles retain certain properties of a solid (intermolecular bonds, fixed size) but gain some properties of a gas (fluid shape). We call this intermediate phase "liquid".

So at that pressure, any molecules with low temperature∗∗ remain solid; some molecules with high temperature become gas; and some molecules with high temperature try to become gas, but get squished down into a liquid.

This is the triple point, where the melting and boiling temperatures are the same. Raise the pressure further, and the melting temperature stays the same∗∗∗ while the boiling point increases. Now you can only have solid and liquid, or liquid and gas.

Analogy: a cinema. During the movie (low temperature), the audience are fixed in place (solid). When the movie is over (high temperature), they leave and spread out freely (gas). But when they stand up to leave, they're in the aisles, not fixed in place but not able to spread out properly (liquid). The liquid phase only exists when many people are trying to leave at the same time (high pressure); if you get up half-way through to go to the loo, you sublime from solid to gas (low pressure).

∗ Yes, I know. Of course liquids exist, but I find thinking of them as "weird" aids understanding.

∗∗ Individual molecules don't have a "temperature". I'm using this as shorthand for "the average kinetic energy of a single molecule of a substance at a certain temperature".

∗∗∗ More or less the same. Also, does anybody know how to use an ordinary * at the start of a line?

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  • $\begingroup$ Downvote for Hollywood physics. $\endgroup$
    – oliver
    May 20 at 18:47
  • $\begingroup$ Perhaps you could explain what you don't like about it? Or what part feels "Hollywood"? I spent a decent amount of time writing this to be accessible to non-physics graduates, if there are problems it would be good to have specifics so I can fix it. $\endgroup$ May 22 at 8:44