0
$\begingroup$

In a Time Varying Magnetic Field like the one shown in the picture below,

enter image description here

if we connect two points on the closed conducting loop using a conducting wire, why is the current flowing zero ?

My textbook says something like "the emf and the potential drop across the connected points will cancel each other out". But I could not understand the meaning of the statement. Can someone please clarify ?

$\endgroup$

1 Answer 1

0
$\begingroup$

Superposition Theorem: The total current in any part of a linear circuit equals the algebraic sum of the currents produced by each source separately.

enter image description here

Let resistance per unit angle subtended at the center (in radians) of conducting loop be $\lambda$.

Total EMF ($E_{total}$ ) around a circular path in a TVMF is $ \dfrac{d\phi}{dt}=A \dfrac{dB}{dt} $ (where $A$ is the area of the circle)

We join points A and B on the loop. Suppose AB subtends an angle $\theta$ at the centre C.

Now considering only minor arc :

$E_{AB,minor}=\dfrac{E_{total}\theta}{2\pi}$

$i_{AB,minor}=\dfrac{E_{total}\theta}{2\pi \lambda \theta}=\dfrac{E_{total}}{2\pi \lambda }$

$E_{AB,major}=\dfrac{E_{total}(2\pi-\theta)}{2\pi}$

$i_{AB,major}=\dfrac{E_{total}(2\pi-\theta)}{2\pi \lambda (2\pi-\theta)}=\dfrac{E_{total}}{2\pi \lambda }$

Now, in the connecting wire AB currents $i_{AB,major}$ and $i_{AB,minor}$ are in opposite directions and cancel each other out, giving a net current of $0$ in the wire by Superposition Theorem.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.