So an expanding universe has the metric $$ds^2 = g_{\mu \nu} dx^\mu dx^\nu = -dt^2 + a(t) ( dr^2+r^2 d\Omega^2)$$ where $d\Omega^2 = d\theta^2 + \sin^2\theta d\varphi^2$ as the usual spherical coordinates.
Specifically, for $a(t) = e^{Ht},$ aka the exponentially expanding universe, we see that there is an $R_{max}$ which after that, you cannot send signals with observers (I think it's called the de Sitter horizon).
Special relativity requires that a physical particle stays within its light cone at all times, but in this model light follows the 'null' trajectory, i.e. $ds^2=0$ or $$dt=a(t) dr$$ This produces an ever narrowing and thinning out light cone as time goes by. My question is regarding this, which I am kind of confused by. If the light cones are getting infinitely narrow and sharper as lots of time goes by, does this mean that the particle's range where it can move gets infinitesimally small to the point where it can't move at all? Because the light cones y-axis is time and x-axis is position (or $r$), so if it's getting thinner and thinner, that means that $r$ for the particle (and thus its wordline) is getting smaller and smaller. What are the implications of that, or maybe I am just misunderstanding? Thank you.