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By chance(playing around really) I saw that a spring(mainly from a pen) placed on a neodymium hard-disk magnet(and then flicked by your finger at the top) makes a nice-effect (see youtube video ). It appears to oscillate in slow-motion(looks like tornado).

Of course, "slow-motion" is purposely simplistic and unscientific - I am very far from a physicist.

Here's the video - http://www.youtube.com/watch?v=n0OJQ1iXZg0&feature=channel_video_title

I was too impatient in the video though, I should have zoomed in on the spring and waited. Sorry about that..

Here's a page about the magnets used: http://www.reuk.co.uk/Hard-Disk-Drive-Magnets-For-Wind-Turbines.htm

Here are the polarities, plus a horizontal profile below:

enter image description here

enter image description here

More details: You really want to use a retractable pen spring, the thin kind. And Hard-drive magnets are key - I think it doesn't work with others. I think it's partly because of the 4-poles of a neodymium magnet. i.e, it's actually two-magnets-in-one. Cigarette lighters also have a long delicate magnet, which is good but too tipsy.
LBNL, supposedly you can stack these magnets, but they seem impossible to separate from the backing-piece. I appreciate any tips or advice.

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    $\begingroup$ If you could work in a link to a video, that would make a fantastic addition to this question. $\endgroup$
    – David Z
    Commented Jul 14, 2011 at 22:45
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    $\begingroup$ i took a few of my neodymium magnets and an assortment of springs and tried to duplicate this with no success, so i'm really interested in seeing a video. $\endgroup$
    – Jay Kominek
    Commented Jul 15, 2011 at 4:40
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    $\begingroup$ @Jay I assume. that Adel used a spring with some windings on the ends touching each other. This electrically shortcut windings could produce that effect, a kind of Waltenhof pendulum. $\endgroup$
    – Georg
    Commented Jul 15, 2011 at 9:37
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    $\begingroup$ The video posted doesn't really show that the spring has sustained vibrations. Any spring would vibrate if one end is fixed, the other free and it is flicked at the free end. $\endgroup$
    – Gsv
    Commented Jul 15, 2011 at 17:33
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    $\begingroup$ pongapundit is right, I don't see the spring doing anything unusual that wouldn't happen if, say, you glued one end to the table. Except that the spring's equilibrium configuration is curved, rather than straight up, although that would be a matter for a different question. $\endgroup$
    – David Z
    Commented Jul 15, 2011 at 17:59

3 Answers 3

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First of all, I am not an expert on magnetism, so this is more of an additional question than answer (cannot add pictures to comments, so thats why its here).

  • In the case of ferrous materials they generate an magnetic field inside material (ok?).

  • Opposite signs attract each other (right?).

  • the position of the spring happens to be the local minimum of potential energy by symmetry principle (or you can actually calculate this).

  • all the other phenomena are just corrections to above phenomena (?).

If all above are summed together, the spring is just oscillating around a local potential energy minimum, because of the magnetic field, not because of the spring properties. This is also why the coin oscillates the same way.

Anyway could you comment on this, I would like to know where I went wrong (if anywhere).

magnet image

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  • $\begingroup$ This means that if you but the spring anywhere else than in the middle of the magnet, it won't work. Also, tilting the spring, tilts the magnetism in iron which costs energy. Reorientation of magnetism in iron isn't cheap energywise. Right? $\endgroup$
    – Juha
    Commented Mar 31, 2012 at 9:38
  • $\begingroup$ Thank You Very Much Juha! I will study this as I still need to learn more physics! $\endgroup$
    – Caffeinated
    Commented Apr 1, 2012 at 21:33
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I'm thinking (assuming the effect is real), that it might be that magnetic effects have lowered the effective spring constant. The total energy in the magnetic field will be different with a long spring than with a short one, because the magnetic permittivity of the spring metal is much higher than air/vacuum. So if one calculates total system potential energy, magnetic, plus internal energy of the spring metal, then one could calculate the mode frequencies (assuming they are long compared to establishing an equilibrium field for a change in spring geometry). The only problem I'm having is I think a longer spring probably means more magnetic field energy, i.e. maybe we would expect the frequency to increase, not decrease.

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The comments section has already pointed out that eddy currents induced in the spring and acted upon by the magnetic field gives rise to a Waltenhof pendulum type of effect. There is also a more dominant and basic effect which is that the base of the spring isn't fixed and so effectively you have two springs in series. For a spring with spring constant $k$ oscillating longitudinally with a mass m on one end $$\omega_0 = \sqrt{\frac k m}$$ For two springs connected in series $$\omega_0 = \sqrt{\frac{k_1k_2}{(k_1+k_2)m}}$$ Vibrating the spring transversely means the expressons for the frequency of oscillation are far more complicated, but the qualitative explanation you're looking for is the same - there is an effective spring connected in series.

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  • $\begingroup$ Where would the eddy currents circulate? The coil is open circuit, not a closed loop. $\endgroup$
    – endolith
    Commented Nov 18, 2011 at 5:29

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