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The variational derivative of the metric with respect to inverse metric

The correct expression is (1). The key point is that the derivative $\partial_\mu$ acts on the entire expression within the functional derivative, not just the delta function. To see this, we start ...
user465226's user avatar
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Functional derivative of gauge fixing condition - Peskin QFT page 295

Hints: Functional/variational differentiation $$\frac{\delta\alpha(x)}{\delta\alpha(y)}=\delta^4(x\!-\!y)$$ here acts on different/independent spacetime points $x$ and $y$; not the same spacetime ...
Qmechanic's user avatar
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