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Yeah, something there is incorrect. I imagine $t\rightarrow\infty$, and see that $\alpha t+v$ will $\rightarrow\infty$ too. But, unless you're using some weird definitions, always $v<c$. Given pro …

Way back when I wondered about such things, Hermann Bondi's "Relativity and Common Sense" cleared up most of the confusion. At Amazon

Astronomers know about this trouble, and stick with what they can measure. For distant galaxies, quasars, cosmic background radiation, etc. they use only the redshift, the "z" value. This is defined …

Write the unit time vector and three unit space vectors. Send each to your given operator and note what comes out. All four results should remain unit space-time length, and all possible pairs shoul …

It's not totally clear what the situation is you're asking about, but it seems to be something like this: If something is causing light to bend - a glass wedge, a gravitational field, magic unicorn …

Such claims as with these electrons should not be taken as strict fact, or used to draw such conclusions about physical reality. For two identical systems, such as two neutral hydrogen atoms, separ …

In the multivector formulation of electromagnetism as developed by David Hestenes, there's only one equation: $\Box F = J$. F and J are space-time objects. F is a "bivector", a 2nd order antisym …

First thing to say is that this system is unstable. Though the simple gravitational and electrostatic forces may be balanced, there is an additional effect for the electrical interaction that won't e …

No, except for the case of the particle being unstable. But I suspect you're thinking of stable particles such as the electron in asking your question. To radiate, the electron has to receive a photo …

I'm not sure this should be an answer - it is really an anti-answer. In Quantum Relativity, David Finkelstein has a list of analogies between QM and relativity, detailing "an extended parallel betwee …