Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
4
votes
Accepted
Four Fermion Interactions
Be careful that there are some integrals, which implies that $S_I^n\neq 0$ !
For instance
$S_I^2=\int_{x_1,x_2,x_3,x_4} (\psi_1^\dagger\psi_1)V_{12}(\psi_2^\dagger\psi_2)(\psi_3^\dagger\psi_3)V_{34} …
2
votes
Accepted
Completing the square for Grassmann variables
The idea is correct (it's called the Hubbard-Stratonovich transformation), but I can't say more without the details of the action. It is discussed in any good textbook on quantum field theory for cond …
3
votes
Accepted
Unitary supermatrices
The problem was in assuming that because one has
$$ (|b|^2-|a|^2)\theta^*=0,$$
then $|b|^2=|a|^2$. Indeed, the only thing it tells you is that $$|b|^2=|a|^2+\sigma \theta^*,$$ where $\sigma$ can be an …
3
votes
Accepted
Contradiction between Fermionic and Grassmann algebra
When writing a path integral starting from a Hamiltonian, one must write down all operators in normal order, as the Grassmann variables correspond to coherent states of the fermionic creation/annihila …
14
votes
Why cannot fermions have non-zero vacuum expectation value?
I think it is a general fact about grassmannian field, and this has nothing to do with Lorentz invariance or other symmetries (you can invent a lot of QFTs without this kind of symmetry, but the VEV o …