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The subfield of optics in which light propagation is approximated in terms of rays. It mainly includes reflection and refraction on surfaces.

2 votes

Snell's law in vector form

Two parts of this answer: (1) a quick sketch of how one gets the result cited and (2) why I believe one can't get a less awkward, more succinct result. Proof Sketch The one thing that the numerical …
Selene Routley's user avatar
1 vote

Light and snell law

Another explanation, further to J.G.'s answer, is simply "owing of symmetry". The answer has to be invariant if we rotate our co-ordianates about the normal, which comes to mean that the only transmis …
Selene Routley's user avatar
3 votes
Accepted

Plane wave focused by lens to a point

The equations you write are not those of a focussing wave (I think you're missing an $i\,\pi$ in your exponent for the $x$ variation for $z>0$). There is no way for the wavefront curvature to change w …
Selene Routley's user avatar
0 votes

Proof that a spherical lens is stigmatic

Actually there is one imaging mode where the spherical lens is a perfect lens: converging all rays, no matter how far from paraxial, to a single focal point. This is the case of the aplanatic sphere, …
Selene Routley's user avatar
2 votes
Accepted

A single-mode optical fiber with a large core

One can make a large core fiber single moded by adjusting the core-cladding index difference so that the waveguide parameter: $$V = \frac{2\,\pi\,\rho}{\lambda}\sqrt{n_{co}^2-n_{cl}^2}$$ is less tha …
Selene Routley's user avatar
0 votes
Accepted

Modes in a subwavelength-diameter optical fiber

The answer is given as part of my answer to your other similar question here. In a dielectric waveguide, nothing special happens: the field spreads out so that it is significantly different from zer …
Selene Routley's user avatar
3 votes
Accepted

The core diameter of the optical fiber is equal to the wavelength of light?

Probably nothing too unusual. The modal field will tend to be a little larger than the core. If the core cladding index difference is small, then the modal field spreads out a long way into the claddi …
Selene Routley's user avatar
0 votes

How is the third-order optics theory equation derived?

I think the project assigned is calling on you to work out something fairly significant for yourself, so be patient and prepared to think fairly hard and not expect the answer to come too trivially. …
Selene Routley's user avatar
3 votes

Proof of Validity of Thick Lens Model by Hamiltonian Formalism or Otherwise

There are very recent devices discovered which this model may not be adequate for (more later), but the model is nonetheless very general. It works for any axially symmetric optical system made of the …
Selene Routley's user avatar
3 votes
1 answer
357 views

Proof of Validity of Thick Lens Model by Hamiltonian Formalism or Otherwise

The paraxial imaging geometry of any axially symmetric optical system can be described by three real parameters: the axial positions of the two principal planes and one focal length (i.e. $f_f=f_b$ in …
Selene Routley's user avatar
2 votes
Accepted

Spherical aberration entity vs. distance from the lens?

It's a bit complicated. There are two competing effects here as one varies the focal length of a spherical lens. Assuming that the beamwidth $w$ is constant, the $f$-number $\frac{q}{w}$ is then propo …
Selene Routley's user avatar
1 vote

Optics for a flat piece of glass

You are correct that the emerging rays are parallel to the incoming ones, but sketch the situation. A ray cone $POQ$ converging to point $O$ with no glass plate converges, instead, in the presence of …
Selene Routley's user avatar
5 votes
Accepted

Beam splitters- Direction of use - again

This is a good question: those marks are mystifying when you meet a beamsplitter for the first time, but I understand from manufacturers that the following can all be reasons for the marks (point 1 is …
Selene Routley's user avatar
17 votes

Why is snow white when water has no color?

Snow is simply a random collection of snowflakes and bits of irregularly shapen bits of ice. Each of these is clear, but a small fraction of the light incident on each clear entity is reflected and sc …
Selene Routley's user avatar
16 votes

How do the laser light return from the retro-reflectors if the Earth is moving?

I presume your 70km comes from the $30{\rm km\,s^{-1}}$ Earth orbital speed about the Sun multiplied by the 2.5 second return trip time to the Moon for a pulse of light. However, recall that, althoug …
Selene Routley's user avatar

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