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Fundamental characteristic property of particles which together with orbital angular momentum acts as the generator of rotations and which doesn't have a classical equivalent but is sometimes compared to and contrasted with classical intrinsic angular momentum.

1 vote

How is the isospin quantum number calculated?

exactly like for a composition of two spin 1/2, you get (0,1) but you have two states composed by the same single states and have the same $S_z$ but have different total spin. I forgot the details abo …
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-1 votes

Hamiltonian in rotating frame

You're applying a Rotation Operator into your magnetic field, as follow $$ B'=R(\theta)B.$$ So we would apply the same for the vector spin operator $$S'=R(\theta)B.$$ The Hamiltonian becomes $$ H=(B …
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1 vote

Representations of Quantum States

you'll still need the spin state, only x-representation is equivalent to p-representation the $\chi $ is the spin state. so you'll need to write $\langle p | \otimes \langle \chi | $
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4 votes
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Degeneracy of states when Spin-Orbit coupling is taken into account

Let's start from the beginning then. $\overrightarrow{L} $ and $\overrightarrow{S} $ are vectors like any other, but they can only take integer length values that we call $\ell$ and $s$. $m_l$ and $ …
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