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What's the difference? $\nabla_\mu e_\nu=\Gamma_{\mu \nu}^\rho e_\rho~\text{ and }~\partial_\mu e_\nu=\Gamma_{\mu \nu}^\rho e_\rho~?$

What's the difference? $$\nabla_\mu e_\nu=\Gamma_{\mu \nu}^\rho e_\rho~\text{ and }~\partial_\mu e_\nu=\Gamma_{\mu \nu}^\rho e_\rho~?$$ In John Dirk Walecka's book 'Introduction to General Relativity',...
Jianbingshao's user avatar
1 vote
1 answer
289 views

What is the difference between $\partial_{\mu}$ and $\partial^{\mu}$? [closed]

I've seen in many books both expressions $\partial_{\mu}$ and $\partial^{\mu}$, which are the covariant and contravariant partial derivatives, respectively, and in one of Susskind's books he defined ...
Antoniou's user avatar
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1 answer
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Differentiating the index notation

I am always confused with the algebra of differentiating the index notation, and have browsed many other posts but still confused. There must be details I have been missing. It would be really ...
user174967's user avatar
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1 answer
61 views

What is $A'$ in the Reissner-Nordstrom metric?

So I was reading this paper on the Reissner-Nordstrom metric and on it they define $A$ as: But they don't define $A'$. Yet $A'$ still ends up in other equations like defining the Ricci tensors: So ...
Ray's user avatar
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6 votes
1 answer
161 views

What does $\delta/\delta t$-derivative represent in tensor calculus?

Some texts, such as Pavel Grinfeld's, talk about a $\delta/\delta t$-derivative whose role (in trajectory analysis of particles using tensor calculus) is pretty obscure to me. For example, the ...
user avatar
2 votes
1 answer
89 views

Does the expression "$𝑑𝑠^2$..." mean the same thing as "$\Delta 𝑠^2$... "?

I reviewed this question but sometimes I'm unsure about delta ($\Delta$) versus differential ($d$) notation. Does the expression "$ds^2=-c^2dt^2+a^2(t)[dr^2 + S_k^2(r)d\Omega^2 ]$" mean the ...
bblohowiak's user avatar
1 vote
1 answer
286 views

Covariant derivative with an upper index in terms of Christoffel symbols

I have encountered expression $$\frac{1}{2}\left(2 \dot{g}_{\mu}{}^{\lambda ; \mu}-\dot{g}_{\mu}{}^{\mu ; \lambda}\right)$$ in a GR paper. Here we assume to be working with the de Sitter metric $g$ ...
Student's user avatar
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1 vote
1 answer
394 views

How to compute divergence of a metric tensor?

I am reading a paper where the author defines the divergence to be $$\left(\delta_{g} \dot{g}\right)_{\mu}:=-\dot{g}_{\mu \kappa;}{}^{\kappa}$$ where $g$ looks like the De Sitter metric, $$g=(3 / \...
Student's user avatar
  • 1,122
0 votes
1 answer
209 views

Tensor notation of covariant derivative

I'm trying to apply Wald's General Relativity equation $3.1.14$: $$\nabla_a{T^{b_1\dots b_k}}_{c_1\dots c_{\ell}}=\overline{\nabla}_a{T^{b_1\dots b_k}}_{c_1\dots c_{\ell}}+\sum_i{C^{b_i}}_{ad}{T^{b_1\...
FonerBalear's user avatar
1 vote
4 answers
2k views

Deriving the Covariant Derivative of the Metric Tensor

First off, I did look through some other questions: Covariant Derivative of Metric Tensor Why is the covariant derivative of the metric tensor zero? https://math.stackexchange.com/q/2174588/ But they ...
M. V.'s user avatar
  • 81
1 vote
1 answer
314 views

What are Connection Forms in General Relativity?

I'm trying to follow an article by H. Ellis (1973), where he developed the first ever metric of a traversable Wormhole (more info here). In pages 105-106 (the end of the 3rd page in the linked file ...
Yoav Zack's user avatar
  • 167
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1 answer
197 views

4-velocity lowering index question

The 4-velocity in contravariant form is given by $$V^\mu=\frac{dx^\mu}{d\tau}$$ for some general co-ordinates $x^\mu$ and proper time $\tau$. Is the 4-velocity in covariant form given by $$V_\nu=V^\...
John Eastmond's user avatar
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2 answers
152 views

Covector basis derivation

On page 65 of Schutz's A first course in General Relativity, he introduces the notation $\phi_{,\alpha}=\partial\phi/\partial x^\alpha$. He then says that $x^\alpha_{\ \ ,\beta}=\delta^\alpha _{\ \ \ \...
martin's user avatar
  • 183
2 votes
1 answer
2k views

How is semicolon derivative notation defined for multiple derivatives?

I have a covector $\eta_\mu$. Then I have some notation which says $$\eta_{\alpha;\beta\gamma}$$ What does this mean? I understand that given a vector $A^\alpha$, that $$A^\alpha_{;\beta}=\nabla_\beta ...
John Doe's user avatar
  • 491
2 votes
2 answers
241 views

Misconception about index notation

I'm going to give an example in General Relativity but this is a question about index notation and coordinate transformations in general. In "Spacetime and Geometry" by Sean Caroll, there is this ...
P. C. Spaniel's user avatar
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1 answer
905 views

On covariant derivative

Let us denote a 1 form on manifold M with $\eta$ which in a chart looks like $\eta=\eta_{\mu}dx^{\mu}$ where $\eta_{\mu}$ are smooth functions on M. Now given the coordinate vector fields $\frac{\...
Hasib's user avatar
  • 25
8 votes
3 answers
3k views

Are indices conventionally raised inside or outside of partial derivatives in general relativity?

If $A_\mu$ is a one-form, then is there a widely accepted convention among physicists about whether the notation $$\partial_\mu A^\mu \tag{1}$$ means "the partial-derivative four-divergence of the ...
tparker's user avatar
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-1 votes
1 answer
124 views

$x'^i_j x^j_k = n\delta^i_k$ rather than $1\delta^i_j$?

These are my calculations $$x'^i_j x^j_k = \sum_{j=1}^n \frac{\partial x'^i}{\partial x^j}\frac{\partial x^j}{\partial x'^k} = \sum_{j=1}^n \frac{\partial x'^i}{\partial x'^k} =n \delta^i_k\ne \delta^...
Display Name's user avatar
1 vote
2 answers
185 views

Tensor index question

I am looking at the solution in the book "Problem book in Relativity and Gravitation" for problem 10.6. I don't think I need to go into the details of the problem (I will do so if need be) because I ...
user41178's user avatar
  • 1,001
0 votes
1 answer
186 views

What is the difference between $\frac{DA^\mu}{D\lambda}$ and $\frac{DA^\mu}{d\lambda}$?

I earlier asked this question How can you have $\frac{DA^\mu}{d\tau}$? I am now wondering: What is the difference between $\frac{DA^\mu}{D\lambda}$ and $\frac{DA^\mu}{d\lambda}$? In the linked ...
Quantum spaghettification's user avatar
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1 answer
119 views

How can you have $\frac{DA^\mu}{d\tau}$?

If a covariant derivative is given by: $$D_\nu A^\mu=\partial_\nu A^\mu +\Gamma^\mu_{\nu \lambda} A^{\lambda}$$ Then how does $\frac{DA^\mu}{d\tau}$ make any sense? Since there are no 'differentials' ...
Quantum spaghettification's user avatar