All Questions
4 questions with no upvoted or accepted answers
3
votes
2
answers
160
views
Acceleration in terms of displacement
I am having problems understanding the derivation of acceleration in terms of displacement. The first step is fine:
$$a(x) = \frac{\mathrm dv(x)}{\mathrm dt}
= \frac{\mathrm dv(x)}{\mathrm dx} \frac{\...
- 131
0
votes
0
answers
95
views
Acceleration as the second derivative of displacement function
Let $x$ be displacement as a function of time $t$ and some other physical quantity $k$ such that
$ x = f(t,k) $
Now,
1) Will the acceleration $a$ be $\frac{\partial^2 x}{\partial t^2}$ or $\frac{d^...
- 23
-1
votes
1
answer
1k
views
Finding kinematic equation with time-varying acceleration
I would like to obtain a relation between initial velocity and distance covered till velocity is zero, with time varying acceleration. For a constant acceleration we can solve:
\begin{align*}
\int_{0}^...
- 99
-3
votes
2
answers
60
views
If x is the position, how and why is one sure that a is displacement and b is acceleration in the given equation? x=a+bt²
I don't understand why a and b have to be displacement and acceleration respectively. Is that because of kinematics fist equation v-u+at?
