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In this Wikipedia article under the section "Heat capacities of a homogeneous system undergoing different thermodynamic processes" there is on line that says: $$ \delta Q=dU+pdV=\bigg(\frac{\partial U}{\partial p}\bigg)_Tdp+\bigg(\frac{\partial U}{\partial T}\bigg)_pdT+p\Bigg[\bigg(\frac{\partial V}{\partial T}\bigg)_pdT+\bigg(\frac{\partial V}{\partial p}\bigg)_Tdp\Bigg] $$ So $U$ and $V$ are assumed to be a function of $p,T$. I saw this step already a few times that a differential of a state function or state variable gets expanded like this. My question now would if, in general, every state function and state variable can get extended with every variable. So for example could I also expand $U$ with $S,V$? like this: $$ dU=\bigg(\frac{\partial U}{\partial S}\bigg)_VdS+\bigg(\frac{\partial U}{\partial V}\bigg)_SdV $$ Or maybe with 4 variables $S,V,p,T$? I know that one requirement is that they are not assumed to be constant. So here $dS,dV,dp,dT\neq0$. But are there any other things I have to keep in mind when expanding a state function like $U$ or a state Variable like $V$?

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  • $\begingroup$ Yes. You need to keep in mind that there is no change of state, and, for a mixture, the amounts of the various species are constant. Also, this applies only to thermodynamic equilibrium states. $\endgroup$ Commented Aug 6, 2023 at 11:03

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For a pure homogeneous phase, Gibbs's rule gives 2 independent variables: $$ (\text{# components})-(\text{# phases}) + 2 = 2 $$ This is the number of independent variables we need to describe the intensive properties of the mixture. In principle we can choose any two among $\{p, T, V, U, S \cdots\}$. Pressure and temperature is a very convenient pair because we can easily measure them and control them experimentally. However, any other set can be used. The equation you wrote, $$ dU = \left(\frac{\partial U}{\partial S}\bigg)_VdS + \right(\frac{\partial U}{\partial V}\bigg)_SdV $$ is correct and is equivalent to $$ dU = T dS - p dV $$

Mixtures The number of independent variables is always determined by Gibbs's rule. In a two-component one-phase system we have three independent variables. We normally choose the first two to come from $p, T, V, U, S \cdots$ and the third one is the mol fraction of one of the two components. Again, this is the number of variables we need to describe the intensive properties of the mixture. We may also write equations for the extensive properties of mixture but I will not go there unless there is a question about it.

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  • $\begingroup$ Ah. So my example of expanding $U$ with respect to $S,V,p,T$ would be wrong because I can only use 2. So only using $S,V$ would be correct. Right ? $\endgroup$ Commented Aug 6, 2023 at 20:36
  • $\begingroup$ That's right: two independent variables provide the complete description of a pure single-phase system. Any two variables from $S$, $V$, $p$, $T$, will do. For example, in the steam tables we tabulate the properties of steam ($V$, $S$, $U$, $H$) as a function of $T$ and $p$. $\endgroup$
    – Themis
    Commented Aug 6, 2023 at 21:46

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