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I am currently inversitgating a system consists of positive and negative point particles satisfying charge neutrality condition. They have a unit charge +1 and -1. In most case, we deal with coulomb interaction potential energy as

$$U = \sum\limits_{i,j} \frac{q_{i}q_{j}}{r_{ij}},$$

where $r_{ij} = |\vec{r}_{i}-\vec{r}_{j}|$. The above equation just considers monopole interaction between charged particles. If I expand $\frac{1}{r_{ij}}$ in terms of spherical harmonics, do you think the spherical harmonics consider multipolar interaction such as dipole and quadrupole between charged particles?

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  • $\begingroup$ are they point particles or finite sized charge distributions (or not-finite multipole distributions)? $\endgroup$
    – JEB
    Commented Jun 3, 2023 at 6:47
  • $\begingroup$ They are point particles $\endgroup$
    – user316761
    Commented Jun 3, 2023 at 6:56

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No. Point particles are electric monopoles, so you don’t consider higher order multiples.

A dipole field defines a direction, and a direction cannot be associated with a point scalar particle.

Now you can say the point has a spin 1/2; but still and electric dipole moment (EDM) violates parity, as it flips sign under reflection while a spin does not.

A vector particle defines a direction, but an EDM violates time reversal …EDM is even, angular momentum is odd.

An electric quadrupole moment is OK, as in the deuteron.

Spin ofc demand a magnetic dipole moment.

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  • $\begingroup$ If I consider particles having a radius r, is my original consideration valid? $\endgroup$
    – user316761
    Commented Jun 5, 2023 at 4:21
  • $\begingroup$ For a spherically symmetric charge distribution per particle, yes, per gausses shell theorem. Of course, the potential inside a particle, the monopole term is $r$, not $1/r$ $\endgroup$
    – JEB
    Commented Jun 5, 2023 at 16:02

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