In standard 1D textbook step potential problems, for $E>V_0$ with $V_0$ the step potential for $x>0$, one finds that for $x<0$ that eigensolutions are of the form $$\psi(x) = A_1e^{i\sqrt{2ME/h^2}x} + B_1e^{-i\sqrt{2ME/h^2}x}$$ and for $x>0$ that $$\psi(x) = A_2e^{i\sqrt{2M(E-V_0)/h^2}x}$$ where we've enforced unstated boundary conditions far from the $x=0$ interface to assert that there is no left-travelling wave for $x>0$.
My question is, why do textbooks state that $|A_2/A_1|^2$ is the "probability of escape". Is this just a manner of speaking, or is there real physical basis to speaking like this? My confusion lies in that probabilities in coordinate representation should be associated with a volume integral of the modulus squared of the wavefunction over an appropriate region.