Kaons are not eigenstates of $CP$: $$ CP|K\rangle =|\overline K\rangle\\ $$ Why do we need to mix them?
One answer I read is "since they both decay into $2$ or $3$ pions". Couldn't they just decay in the same thing and that's it? There are many other particles that happen to decay the same way, but we don't mix them.
*Addendum. Citing from "Mixing and Oscillations of Particles" by Andrzej K. Wroblewski:
In 1955 Murray Gell-Mann and Abraham Pais analyzed the behavior of neutral particles under the operation $C$ of charge conjugation which changes every particle into its anti-particle. According to the proposed scheme of classification of $K$ mesons, the neutral kaon $K^0$ was assumed to possess an anti-particle $\overline{K}^0$ distinct from itself. Gell-Mann and Pais were able to show that in that case the neutral kaon must be considered to be a “particle mixture”, exhibiting two distinct lifetimes and different decay modes.
What were the reasons that brought Gell-Mann and Pais to this conclusion?