We have a well understood interacting electromagnetic system, an electromagnetic wave interacting with an atom. We use perturbation theory to calculate what happens in such a system. The result is of course the phenomenon of stimulated emission, which has an important application in LASERs.

My question: Is there any way to do the gravitaional counter-part of the problem, that is interaction of a black hole with a gravitational wave(well, I agree that the correspondense is approximate of course), may be using AdS/CFT ?


1 Answer 1


I don't know why you need AdS/CTF correspondence for that? There is a good derivation found here (page 64 to 90). To give a quick overview:

You can calculate the propagation of gravitational waves on a background metric using pertubation theory in first order. You start with a pertubation of the metric tensor given by: \begin{equation} \widetilde{g}_{\mu\nu} =g_{\mu\nu}+\delta g_{\mu\nu} \qquad\text{with}\qquad |\delta g_{\mu\nu}|<1 \end{equation} \begin{equation} \widetilde{g}^{\mu\nu} =g^{\mu\nu}-\delta g^{\mu\nu} \qquad\text{with}\qquad |\delta g_{\mu\nu}|>1. \end{equation} The different signs were explained by me here already. You can now calculate the Christoffel symbols, the Riemann curvature tensor and the Einstein tensor only in first order of the pertubation.

In a vacuum, we get the equation $G_{\mu\nu}[g]=0$ (equivalent to $R_{\mu\nu}[g]=0$) for the background metric and $\delta G_{\mu\nu}=0$ for the gravitational waves out of the field equations. Using a corresponding pertubation tensor (similar to the correspondence between the Ricci and Einstein tensor): \begin{equation} \delta g_{\mu\nu}' =\delta g_{\mu\nu}-\frac{1}{2}(g^{\kappa\lambda}\delta g_{\kappa\lambda})g_{\mu\nu}, \end{equation} \begin{equation} \delta g_{\mu\nu} =\delta g_{\mu\nu}'-\frac{1}{2}(g^{\kappa\lambda}\delta g_{\kappa\lambda}')g_{\mu\nu}, \end{equation} the equation describing the scattering of gravitational waves is given by: \begin{equation} \square\delta g_{\mu\nu}' +2R_{\kappa\mu\lambda\nu}\delta{g^{\kappa\lambda}}'=0. \end{equation} For the Schwarzschild metric in particular using this equation results in the Regge-Wheeler equation.

  • $\begingroup$ I think the first link is broken. Could you please give which reference is that? $\endgroup$
    – Eden Zane
    May 28, 2022 at 13:41
  • 1
    $\begingroup$ Thanks for the remark, it's fixed now. It's "Gravitational Waves" by Claus Lämmerzahl and Volker Perlick from the University of Bremen. $\endgroup$ May 28, 2022 at 21:48

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.