While humidifying a room in my home, measuring the Temperature and Relative Humidity (T&RH respectively) every 8 hours, I noticed that RH rises and falls with T when it should be the inverse.
- I don't understand how this happens.
- Shouldn't the RH% drop as T rises and inversely so?
- Shouldn't the avg. RH be much higher than 37% given the context below?
- I've tested the accuracy of my hygrometer using the moist salt test (it accurately reads 75% RH in a sealed bag over an 8hr period).
For context:
I built four humidifiers each using a 200mm/800RPM cooling fan, a wick, and a bucket. They can each evaporate 64fl.oz. of H20 in 12 hours, roughly 2 gallons/day.
The room is kept at a constant 20°C and I get a pretty consistent 36-37% RH, except for when the heat kicks on and the RH goes up ~4%.
Follow-Up, which is why I actually came here:
I'm trying to estimate how much water is needed to fully saturate the air in my room, and based upon the maths I used, I don't trust the results I have.
Given the following:
- Temperature = 20°C (68°F)
- Room Volume = 61.1644m³ (2160 ft³)
- Grams H2O per 1kg/m³ = 17.3g (10-3 kg/m3)
- Grams per Cup (8 fl.oz.) = 240g
I conclude that:
- Total Grams of water the room can hold at 20°C = 1,058g (61.1644m³×17.3g)
- Cups Needed to Saturate = 4.41 (1,058÷240)
Is this correct? In other words, not compensating for ventilation rates or air changes per hour (ACH), would 4.41 cups of water saturate the air in the room if it were instantly vaporized and mixed evenly throughout the air? That seems like such a small amount of water.
Sources
Air - Maximum Moisture Carrying Capacity https://www.engineeringtoolbox.com/amp/maximum-moisture-content-air-d_1403.html