The main equation of Quantum Mechanics (QM) is the Schrodinger Equation (SE): $$i\hbar\frac{\partial \psi (x,t)}{\partial t}=H(x,t)\psi(x,t)$$ Why is this equation so important? It's important because if we know the state (the wavefunction) of a particle at a time $t_0$ SE allows us to predict, to know, the state (wavefunction) of the particle at any other time $t$.
There is also another fundamental thing to know about this topic:
- if the Hamiltonian is time independent
- and if the wavefunction at the time $t_0$ is an eigenfunction of the Hamiltonian ($H\psi(x,t_0)=E\psi(x,t_0)$)
then finding the wavefunction at a time $t$ get's a lot easier! In fact, in this case, we can prove that:
- The wavefunction is factorizable: $\psi (x,t)=\phi(x)g(t)$
- $g(t)$ must equate: $$g(t)=\exp{\left[\frac{1}{i\hbar}E(t-t_0)\right]}$$
- $\phi(x)$ is constant (this is obvious given 1.) and is indeed the eigenfunction of $H$ (also obvious given 1.): $$\phi(x) \ | \ H\phi(x)=E\phi(x)$$
The equation $$H\phi(x)=E\phi(x) \tag{1}$$ is of course the eigenfunction equation for $H$, but it's also called: time independent Schrodinger equation.
My question is: is that it? Am I missing something? If this is it I don't really understand why (1) deserves a name of its own, why it's called "Schrodinger equation".. (1) seems to be simply a part of a mathematical trick to find the solutions to a differential equation under some special initial conditions.
If, in a QM problem/exercise, the wavefunction $\psi(x , t_0)$ is not an eigenfunction of $H$ then the time independent Schrodinger equation is useless, am I right? It is only useful in problems when the initial state of the particle happens to be a stationary state (synonym for eigenfunction of H), right?
Are there other uses for the time independent Schrodinger equation?