I was calculating the trace of two Dirac matricies and I used their anti-commutation relations:
$$ Tr(\gamma^{\mu} \gamma^{\nu}) = -Tr(\gamma^{\nu} \gamma^{\mu}) - Tr(2\eta^{\mu\nu}) $$
$$ = - Tr(\gamma^{\mu} \gamma^{\nu}) - 8 $$
$$Tr(\gamma^{\mu} \gamma^{\nu}) = -4 $$
where I used that $2Tr(\eta^{\mu\nu})=8$, but I dont understand why it gives: $Tr(\gamma^{\mu} \gamma^{\nu}) = -4\eta^{\mu\nu}$, where does the metric come from?
By the same token, when calculating $ Tr(\gamma^{\mu} \gamma^{\nu}\gamma^{\alpha} \gamma^{\beta})$:
$$ Tr(\gamma^{\mu} \gamma^{\nu}\gamma^{\alpha} \gamma^{\beta}) = Tr( - \gamma^{\beta} \gamma^{\mu}\gamma^{\nu} \gamma^{\alpha} - 2\eta^{\mu\beta} \gamma^{\nu} \gamma^{\alpha} + 2\gamma^{\mu} \gamma^{\alpha} \eta^{\nu\beta} - 2\gamma^{\mu} \gamma^{\nu} \eta^{\alpha\beta}) $$
$$ 2Tr(\gamma^{\mu} \gamma^{\nu}\gamma^{\alpha} \gamma^{\beta}) = - 2\eta^{\mu\beta} Tr( \gamma^{\nu} \gamma^{\alpha}) + 2 \eta^{\nu\beta}Tr(\gamma^{\mu} \gamma^{\alpha}) - 2 \eta^{\alpha\beta}Tr(\gamma^{\mu} \gamma^{\nu} )$$
I dont understand why the Minkowski matrix comes out in this case in order to give the desired relation. Can someone tell me how to do it correctly?