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I have been studying Raychaudhuri equation and focusing theorem related to it. Focusing theorem says that if the strong energy condition is satisfied and rotation tensor vanishes $\omega_{ab}$=0 then rate of expansion is negative. Frobenius theorem for timelike vector says that timelike geodesic is hypersurface orthogonal iff $\omega_{ab}$=0.

I was wondering to apply this in flat spacetime but I can't find any suitable timelike geodesic in flat spacetime which would be hypersurface orthogonal and d\theta /d\tau is negative. Can anyone help with this?

If I have any such geodesic and as in flat spacetime Riemann curvature tensor would be 0 therefore only expansion term and shear tensor term would be left in Raychaudhuri equation which can be found through simple computation and hence focusing theorem could be satisfied in flat spacetime.

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  • $\begingroup$ @Umaxo Actually i am also not able to find the vector field which seems to be expanding and simultaneously is hypersurface orthogonal. $\endgroup$ Commented Sep 16, 2020 at 12:13
  • $\begingroup$ I couldn't follow your argument where you said geodesic deviation being zero implies no expansion. Can you please elaborate on that? Thanks $\endgroup$ Commented Sep 16, 2020 at 12:28
  • $\begingroup$ sorry I was probably just being stupid $\endgroup$
    – Umaxo
    Commented Sep 16, 2020 at 12:40
  • $\begingroup$ Isn't a bunch of parallel lines hypersurface orthogonal? $\endgroup$
    – Javier
    Commented Sep 21, 2020 at 17:47
  • $\begingroup$ For parallel lines d\theta/ d\tau would be zero but i was looking for example where it would be negative. Sorry for not mentioning this explicitly in the question. I have edited it. $\endgroup$ Commented Sep 27, 2020 at 2:13

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In flat spacetime, let $(t,x,y,z)$ be a global inertial cartesian coordinate system. Then the lines with $x,y,z$ fixed are orthogonal to the hypersurfaces of constant $t$.

This is the simplest case possible: trajectories of infinitely many inertial observers in rest relative to each other.

If you apply Raychaudhuri to this example, you will find $\dot{\theta}=0$ since $\theta_0 = 0$ initially, and thus $\theta = 0$ for any $t$.

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  • $\begingroup$ Thanks, but i was looking for any example for which $d\theta / d\tau$ is negative. I think i didn't explicitly mentioned it. I'll edit the question. $\endgroup$ Commented Sep 27, 2020 at 2:10

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