0
$\begingroup$

I am familiar with coordinate transformations in the common case. (Say, polar to cartesian and back)

I have recently been introduced to the definition of a differentiable manifold. Is it correct to say that, in Newtonian physics for instance, if you are transforming a vector from Cartesian to Polar, what you are doing is mapping the vector from one chart to another and expressing it in the coordinate-induced basis of the new chart?

Improve this question
$\endgroup$
4
  • 1
    $\begingroup$ Two comments: (1) this probably belongs in Math.SE rather than Physics and (2) 'Yes' is too short an answer to post... $\endgroup$
    – jacob1729
    Commented May 16, 2019 at 16:47
  • $\begingroup$ Yes a chart on a configuration manifold I guess $\endgroup$
    – Mathphys meister
    Commented May 16, 2019 at 17:11
  • $\begingroup$ Yes. Indeed too short. $\endgroup$
    – Anders Sandberg
    Commented May 16, 2019 at 20:56
  • $\begingroup$ I can't accept an answer because as you said, "Yes" is too short, but I want to say thank you for providing me with the answer to my question. $\endgroup$
    – azani
    Commented May 18, 2019 at 7:06

0

Reset to default

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Browse other questions tagged or ask your own question.