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I'm new to classical mechanics and learned a new cool thing, second type equations of Lagrangian Mechanics. So, I was just testing if it really works or not. So, I made a question myself to test it, but I think that I've some problem here.

Figure

First, assume the $x$ coordinate of the ball of mass $m$. Initially, it's at $x=0$, under the influence of Gravity it should fall (assuming the setup is in such a way that Gravity is acting from downwards.)

So, the cool equation says that :

$$\displaystyle{\boxed{\boxed{ \dfrac{d}{dt} \left ( \dfrac{\partial L}{\partial {x'} } \right) - \dfrac{\partial L}{\partial x} = 0 }} \quad \dots \quad (*)}$$ Where, $L = K.E. - P.E. = ( mg \sin \theta x) - (mg \sin \theta h)\quad \dots \quad (1)$

However using the Euler-Lagrange equation (*) with the Lagrangian (1) does not give me a sensible answer, so my question is where is my mistake?

So, I've calculated K.E. here as: $K = \frac 1 2 m v^2 = \frac 1 2 m (2(g \sin \theta) x) \quad \dots \quad (\text{As }v^2 = u^2 + 2as)$

and $P = mgh = mg\sin \theta(h - x )$

The issue might be to do with using $v^2=2as$ in the kinetic energy (as suggested in comments) but I don't see why this is improper.

So, Why I can't substitute the Velocity equations in that Lagrangian Equation (That Kinetic energy part).

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  • $\begingroup$ Suggestion: Replace second type of equations of Lagrangian Mechanics with Lagrange equations of second kind. $\endgroup$
    – Qmechanic
    Commented Apr 6, 2019 at 18:17
  • $\begingroup$ Comments are not for extended discussion; this conversation has been moved to chat. $\endgroup$
    – ACuriousMind
    Commented Apr 6, 2019 at 18:38
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    $\begingroup$ @alephzero This is being discussed on meta. $\endgroup$
    – user199113
    Commented Apr 6, 2019 at 19:35

1 Answer 1

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  1. OP's calculation (v7) violates the rule is that one is not allowed to use equations of motion in the Lagrangian $L(q,v,t)$ before all differentiations in Lagrange equations have been carried out. This is mainly because generalized positions $q^i$, generalized velocities $v^j$, and time $t$ are independent variables in the Lagrangian $L(q,v,t)$, cf. e.g. this Phys.SE post.

  2. A similar rule says that one is not allowed to use equations of motion in the action prior to variations.

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  • $\begingroup$ hello, can you write the Lagrangian function in this case, please? $\endgroup$
    – user208739
    Commented Apr 25, 2019 at 12:22

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