The relation between magnetic flux density $(\vec{B})$ and magnetic field intensity $(\vec{H})$, in general, is:

\begin{equation} \vec{B}=\mu_0(\vec{H}+\vec{M}) \tag{1} \end{equation}

One of my colleagues told equation (1) can be written as:

\begin{equation} \vec{B}=\mu\vec{H} \tag{2} \end{equation} where $\mu$ is the permeability of the medium.

Is this correct in general? If yes, how can we derive $(2)$ from $(1)$?


The magnetization is gained as a result of an external magnetic field applied, so there must be a relation between the two vectors (i.e. a transformation) that takes the form of a tensor function. This transformation is known as the magnetic susceptibility.

Your equation $\mathbf{B} = \mu \mathbf{H}$ is only correct in linear homogeneous isotropic magnetic materials. "Linear" means that the magnetization is in the same direction as the magnetic field (i.e. the tensor function reduces to a scalar function), "homogeneous" means that the susceptibility is the same throughout, and "isotropic" means that susceptibility is the same in all directions. So, to answer your question, it is not correct in general. Most materials, however, do behave in this way when the applied magnetic field is not too strong.

In such a material, the magnetization is directly proportional to the applied magnetic field: $$\mathbf{M} = \chi_m \mathbf{H}$$ where $\chi_m$ is the magnetic susceptibility. So we have $$\mathbf{B} = \mu_0 (\mathbf{H} + \mathbf{M}) = \mu_0 (1 + \chi_m) \mathbf{H} = \mu \mathbf{H}$$ The quantity $(1 + \chi_m)$ is known as the relative permeability.

| cite | improve this answer | |

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.