# Inductors problem

In figure, the switch is in the position 1 for a long time. Then the switch is shifted to position 2 at $t=0$. At this instant, the value of $i_1$ and $i_2$ is

Well I'm confused over what will happen here. So the current through the inductor in middle wire will be $\frac{E}{R}$ just after shifting the switch. But what about the inductor in the right most wire?

There are three possibilities for the rightmost inductor according to me-

1. The current in the closed loop now is same throughout. So the current through the inductor also equals $\frac {E}{R}$.

2. The inductor opposes the current in the circuit. So the current through it is zero at $t=0$

3. The total flux of both the inductors remains constant.

So what exactly happens here and why?

• Are you asking what is the current in the circuit at the instant $t=0^+$ ? – Goldname Jul 1 '18 at 21:40

Option 1 would not work, since it would require more energy than is available: $2$x$\frac {LI^2} 2 > \frac {LI^2} 2$