Your curve $C_2$ is not a straight line.
There is an easy way to see that $C_2$ isn't a straight line without having to resort to differential geometry. A straight line is the shortest distance between two points$^1$, so consider two points on $C_2$ on opposite sides of the pole:
I've drawn $C_2$ as the red curve on a perspective diagram and also in the side on view. We'll take the sphere to have unit radius for convenience.
$C_2$ is a circle of radius $r = \sin\theta$ so the distance between opposite points measured along the circle is just half the circumference:
$$ s_1 = \tfrac{1}{2}2\pi r = \pi\sin\theta $$
Compare this with the distance between the points if we follow the line through the pole shown on the right diagram by the dashed line above the sphere. This is a segment of a great circle so the length of the segment is:
$$ s_2 = 2\theta $$
And for $0 \le \theta \le \pi/2$ the distance $s_2$ is always smaller than $s_1$. That means the curve $C_2$ cannot be a straight line because it isn't the shortest distance between the points. Rather than go though the algebra to show that $\pi\sin\theta \ge 2\theta$ I simply drew a graph to show this:
Note that the two distances are equal only for the trivial case where $C_2$ has zero radius and $\theta = \pi/2$ i.e. when $C_2$ is a great circle.
$^1$ not strictly true. A straight line extremises the path length, but let's overlook this to keep the argument simple.