6
$\begingroup$

I am trying to understand the difference between the 2-point vertex function and the self energy. In many presentations, they are described in ways that seem nearly equivalent, yet as I work through the details I run into seemingly nonsensical statements.

To start with definitions, we know that the 2-point vertex $\Gamma^{(2)}$ is characterized by $\Gamma^{(2)} = G_c^{-1}$, the inverse of the 2-point connected Green's function. The self-energy $\Sigma$ is the sum of all 1-particle irreducible (1PI) diagrams of the two-point function after amputating the external legs.

It is also said that $\Gamma^{(n)}$, the $n$-point vertex, is said to be the sum of all amputated 1PI diagrams with $n$ external legs. This statement is not a definition, but a derived consequence. However, this statement seems strange to me in the case $n=2$, in which case it would be equivalent to saying $\Gamma^{(2)} = \Sigma$.

We know that $G_c^{-1} = G_0^{-1} - \Sigma$, where $G_0$ is the free propagator. If $\Gamma^{(2)} = \Sigma$, then we would arrive at the nonsensical statement $2\Gamma^{(2)} = G_0^{-1}$. This seems to imply that $\Gamma^{(2)}$ should not be thought of as the sum of all the 1PI diagrams for the amputated 2-point correlator.

Am I missing something here, or are textbooks being imprecise in the statement that $\Gamma^{(n)}$ is the sum of all amputated 1PI diagrams with $n$ external legs?

$\endgroup$
2
  • $\begingroup$ Related: physics.stackexchange.com/q/193419/2451 $\endgroup$
    – Qmechanic
    Commented Oct 3, 2017 at 18:07
  • $\begingroup$ One should not forget that the effective action (when obtained perturbatively) contains both the bare action and the diagrams. The diagrams are then 1PI due to the construction of $\Gamma$, but there is also a contribution (usually for small $n\leq 4$) from the bare action. $\endgroup$
    – Adam
    Commented Jul 1, 2018 at 8:19

1 Answer 1

2
$\begingroup$

It really looks like there is missing $n > 2$ for that definition. Clearly 1-PI diagrams for n-point functions with $n > 2$ are what the vertex function is, because none of them can be amputated if stacked together. On other hand, with 2-point function one can always stack 1-PI diagrams by connecting them in such way that all but one of them can be amputated.

$\endgroup$
1
  • $\begingroup$ Sorry to comment on an older post but I am having the same problem as the original poster where I don't see what's special about $\Gamma^{(2)}$. What do you mean by "stacking" 1-PI diagrams? $\endgroup$
    – CBBAM
    Commented Mar 29 at 6:13

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.