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I'm reading from "Quantum Physics for Dummies", by Steven Holzner. In chapter two, entitled "Entering the Matrix: Welcome to State Vectors", the author introduces the notation for a gradient of a wave function.

Gradient operator

I understand all of the complement, but what confuses me is the use of the relationship operators, what do they signify in this context? How can you compare a partial derivative with a basis vector?

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    $\begingroup$ Having seen only these few lines I would definitely recommend to get the basics from some other book. Gradients of state vectors are a gross abuse of notation. $\endgroup$
    – noah
    Commented Sep 15, 2017 at 16:03
  • $\begingroup$ @noah would you have any recommendations? $\endgroup$ Commented Sep 15, 2017 at 16:04
  • $\begingroup$ Not off the top of my head, no. But I'm sure you can find some at physics.stackexchange.com/questions/33215/…. I just felt the need to mention that this is not a quality source. $\endgroup$
    – noah
    Commented Sep 15, 2017 at 16:07
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    $\begingroup$ Throw the book away. $\endgroup$
    – DanielC
    Commented Sep 15, 2017 at 16:23

2 Answers 2

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This is typeset terribly. What it is supposed to mean is ket-vectors in Dirac notation, which are usually set with an "rangle" ($\rangle$) and "langle" ($\langle$), not > and <.

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Unfortunately the author misuses the bra-ket notation. A state should be written in the form

$$ | \phi \rangle $$

instead of $|\phi >$. This way, the gradient should appear as

$$ \nabla |\psi\rangle = \frac{\partial}{\partial x}|\psi\rangle {\bf i} + \frac{\partial}{\partial y}|\psi\rangle {\bf j} + \frac{\partial}{\partial z}|\psi\rangle {\bf k} $$

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  • $\begingroup$ I think we can assume that was more related to the publisher than the author, but that really doesn't help me $\endgroup$ Commented Sep 15, 2017 at 15:56
  • $\begingroup$ Oh my god. I'm a moron. 😂😂😂 $\endgroup$ Commented Sep 15, 2017 at 15:57

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