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I'm trying to understand 3:02 in this video:

https://www.youtube.com/watch?v=AlIlkn3OxMI&t=184s

He seems to be saying that the measurement of a property one photon has no effect on the other. So the other photon doesn't change at all from before the measurement to after the measurement of the first photon? So it already had whatever property the experimenter measured before the measurement took place?

Isn't this precisely what Bell's Theorem shows isn't true?

The version of Bell's Theorem I'm using is stated here:

https://en.wikipedia.org/wiki/Bell%27s_theorem

as "No physical theory of local hidden variables can ever reproduce all of the predictions of quantum mechanics."

I understand what Murray Gell Mann is saying in the video is that the other photon has certain pre-existing properties. We just learn about those properties when measuring on the first photon. Aren't those local hidden variables?

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  • $\begingroup$ can you give a link to what form of Bell's theorem you are referring to? $\endgroup$
    – anna v
    Commented Jul 16, 2017 at 7:27
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    $\begingroup$ The photon as it exists in the entire set of decoherent histories which includes what happened in the counterfactual history where you found a different result for your photon, isn't affected. $\endgroup$ Commented Jul 16, 2017 at 7:32
  • $\begingroup$ @CountIblis, so these counterfactual histories are "real" in some sense? $\endgroup$ Commented Jul 16, 2017 at 7:37
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    $\begingroup$ local means the same (x,y,z,t) , the two photons have different (x,y,z,t). quantum mechanics is non local, i.e. the wave function describes the whole system at different (x,y,z,t) . see this view of Bells theorem scholarpedia.org/article/Bell%27s_theorem . $\endgroup$
    – anna v
    Commented Jul 16, 2017 at 7:37
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    $\begingroup$ In the Many Worlds Interpretation one assumes that the counterfactual histories are real. If you assume that they are not real, then you still can't assume that the actual history out of the set of all the histories is predetermined as that will lead to a conflict with Bell's theorem. But this view leads to a hidden nonlocality, it's not going to bring QM in conflict with special relativity. I summarized the problem in this question. $\endgroup$ Commented Jul 16, 2017 at 21:17

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