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Does a solution of water and NaCl increase its volume of the same amount of the volume of salt added? Thank you

Does the ions Na+ and Cl- taken separately ,occupy more space than the binded molecule?

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    $\begingroup$ Would Chemistry be a better home for this question? $\endgroup$
    – Qmechanic
    Commented Mar 18, 2017 at 10:32
  • $\begingroup$ Perhaps it is,sorry $\endgroup$ Commented Mar 18, 2017 at 12:35

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Suppose we take $100$g of an $x$% by weight solution of sodium chloride, so we have $x$g of salt and $100-x$g of water. The volume of $x$g of salt is:

$$ V_S = x/\rho_S $$

where $\rho_S$ is the density of solid salt. Likewise the volume of the water is:

$$ V_W = (100-x)/\rho_W $$

Suppose when we dissolve salt in water the volumes just add i.e.

$$ V_\text{total} = V_S + V_W = x/\rho_S + (100-x)/\rho_W $$

then the density of our $x$% salt solution would be:

$$ \rho_\text{sol}(x) = \frac{100}{x/\rho_S + (100-x)/\rho_W} \tag{1} $$

The density of salt is $2.165$g/cm$^3$, and we'll take the density of water to be $1$g/cm$^3$, so we can use equation (1) to calculate what the density would be if the volumes just added and we can compared this with the experimentally measured density. I did this in Excel and got:

$$\begin{matrix} x & Equation (1) & Experimental & Constant Volume\\ 0 & 1.000 & 1.000 & 1\\ 0.5 & 1.003 & 1.002 & 1.005\\ 1 & 1.005 & 1.005 & 1.01\\ 2 & 1.011 & 1.013 & 1.02\\ 3 & 1.016 & 1.020 & 1.03\\ 4 & 1.022 & 1.027 & 1.04\\ 5 & 1.028 & 1.034 & 1.05\\ 6 & 1.033 & 1.041 & 1.06\\ 7 & 1.039 & 1.049 & 1.07\\ 8 & 1.045 & 1.056 & 1.08\\ 9 & 1.051 & 1.063 & 1.09\\ 10 & 1.057 & 1.071 & 1.10\\ 12 & 1.069 & 1.086 & 1.12\\ 14 & 1.081 & 1.101 & 1.14\\ 16 & 1.094 & 1.116 & 1.16\\ 18 & 1.107 & 1.132 & 1.18\\ 20 & 1.121 & 1.148 & 1.20\\ 22 & 1.134 & 1.164 & 1.22 \end{matrix}$$

The experimental densities are greater than the densities calculated using equation (1) i.e. just adding the volumes of the salt and water. That shows the volumes do not simply add but the total volume is less than the sum of the two volumes.

Chart of data

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  • $\begingroup$ Suppose we dissolved slat in water and the volume of the water didn't change: then the density of our $x$% salt solution would be: $$ \rho_\text{sol}(x) = \frac{100+x}{100} \tag{2} $$ Yeah, so our measured densities are higher than that - there is some increase in volume. $\endgroup$
    – JMLCarter
    Commented Mar 18, 2017 at 12:15
  • $\begingroup$ @JMLCarter: hmm, good point. I could add a fourth column giving the density if the volume remained at 100 cm$^3$. $\endgroup$ Commented Mar 18, 2017 at 13:05
  • $\begingroup$ ...would give a bound on the other side. Chance for least squares to be applied too depending how far we want to go. $\endgroup$
    – JMLCarter
    Commented Mar 18, 2017 at 13:26
  • $\begingroup$ @JMLCarter: aha, you've added the fourth column for me! Thanks :-) $\endgroup$ Commented Mar 18, 2017 at 20:56
  • $\begingroup$ Hello, we are talking about a solution with a salt that splits in two ions... and if we had for example CaCl2,that splits in 3 ions? How would the volume change? $\endgroup$ Commented Aug 17, 2017 at 16:04

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