# What would all the forces on a space elevator be as it moves up and down?

At the bottom, the acceleration due to gravity would be g. At the top, it would be something like .8g... But would the total acceleration effectively be 0 like on the ISS? How would the acceleration change, then, as it moves up? Or, because the top of the elevator would be well beyond the center of gravity of the system, would its acceleration have an upward component at the top?

There will be a upward component of acceleration because the space lift is not in geostationary orbit. the space lift with respect to the earth at the altitude of 330-450 km has not attained the orbital velocity but is at the velocity of $R*\omega,R\to \text{radius of earth+lift length},\omega \to \text{angular velocity of earth}$ which is not sufficient to experience the effect of zero gravity.