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I have an Hamiltonian problem whose 2D phase space exhibit islands of stability (elliptic fixed points).

I can calculate the area of these islands in some cases, but for other cases I would like to use Mathematica (or anything else) to compute it numerically.

The phase space looks like that :

alt text

This is a contour plot make with Mathematica. Could anyone with some knowledge of Mathematica provide a way to achieve this ?

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  • $\begingroup$ Calculate the area or plot the graph? $\endgroup$
    – kennytm
    Commented Nov 3, 2010 at 6:35
  • $\begingroup$ I did the plot, from the plot, or from the function I want to calculate the area. $\endgroup$
    – Cedric H.
    Commented Nov 3, 2010 at 7:01
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    $\begingroup$ This actually seems like a computing question that happens to arise in a physical application, not really a physics question. Or is it just me? $\endgroup$
    – David Z
    Commented Nov 3, 2010 at 7:41
  • $\begingroup$ Asking here, maybe I'll find someone using Mathematica for physics, I don't think asking in SO is a better idea. $\endgroup$
    – Cedric H.
    Commented Nov 3, 2010 at 8:02
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    $\begingroup$ I think this one is grey area, leaning towards computing rather than physics. But not voting to close because you attached a nice graph. Always like a good graph. $\endgroup$ Commented Nov 3, 2010 at 10:29

1 Answer 1

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There is rather nice function in Mathematica 7, which allows one to integrate over an arbitrary complicated region. It is Boole:[True,False]$\to${1,0}. Below is just an example taken from Mathematica Documentation Center. If you have a 2D area defined by the inequality $4 x^4-4 x^2+y^2\leq 0$,

alt text

you can integrate any function $f(x,y)$ over this domain as follows:

Integrate[f[x,y] Boole[y^2 - 4 x^2 + 4 x^4 <= 0], {x, -Infinity,Infinity}, 
{y, -Infinity,Infinity}]

For example, if $f(x,y)$ is unity then it gives you the total volume of the integration domain:

In[1]:= Integrate[Boole[y^2 - 4 x^2 + 4 x^4 <= 0], {x, -Infinity,Infinity}, 
{y, -Infinity,Infinity}]
Out[1]= 8/3

In fact, you can use any condition you want, including that is determining your islands of stability. Numerical integration is also possible:

In[1]:= NIntegrate[Boole[y^2 - 4 x^2 + 4 x^4 <= 0], {x, -Infinity,Infinity}, 
{y, -Infinity,Infinity}]
Out[1]= 2.66667
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  • $\begingroup$ By the way, Mathematica is a grate tool widely used by physicists in various areas. I think it is worth to collect questions about it here (by using the new tag "Wolfram Mathematica", not just "Mathematica"). $\endgroup$ Commented Nov 12, 2010 at 2:20
  • $\begingroup$ Thanks, it is not exactly what I was looking for but it might do the trick. About the tags: these two can be made synonyms. $\endgroup$
    – Cedric H.
    Commented Nov 12, 2010 at 11:37

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